The sum of three odd integers will never be an even integer (0).
This proof is impossible.
Using the normal distribution, it is found that:
a) There is a 0.947 = 94.7% probability that a randomly selected bag contains between 1000 and 1500 chocolate chips, inclusive.
b) There is a 0.0392 = 3.92% probability that a randomly selected bag contains fewer than 1025 chocolate chips.
c) 0.3446 = 34.46% of bags contains more than 1200 chocolate chips.
d) The bag is in the 91st percentile.
In a normal distribution with mean and standard deviation, the z-score of a measure X is given by:
In this problem:
Item a:
The probability is the p-value of Z when X = 1500 subtracted by the p-value of Z when X = 1000, thus:
X = 1500:
has a p-value of 0.9726.
X = 1000:
has a p-value of 0.0256.
Then, 0.9726 - 0.0256 = 0.947
There is a 0.947 = 94.7% probability that a randomly selected bag contains between 1000 and 1500 chocolate chips, inclusive.
Item b:
This probability is the p-value of Z when X = 1025, thus:
has a p-value of 0.0392.
There is a 0.0392 = 3.92% probability that a randomly selected bag contains fewer than 1025 chocolate chips.
Item c:
This proportion is 1 subtracted by the p-value of Z when X = 1200, thus:
has a p-value of 0.3446.
0.3446 = 34.46% of bags contains more than 1200 chocolate chips.
Item d:
This percentile is the p-value of Z when X = 1425, thus:
has a p-value of 0.91.
The bag is in the 91st percentile.
A similar problem is given at brainly.com/question/13680644
The probability and percentiles can be found using the z-score formula and then looking these z-scores up in the standard normal distribution table.
In this question, we're dealing with a normal distribution. For a normal distribution, probabilities can be calculated using the z-score formula which is given by Z = (X - μ) / σ, where X is the value from which you want to find the probability, μ is the mean and σ is the standard deviation.
(a) To find the probability that a randomly selected bag has between 1000 and 1500 chocolate chips, we need to find the z-scores for both 1000 and 1500 and then find the area between these two z-scores in the standard normal distribution table. (b) To find the probability that a randomly selected bag has less than 1025 chips, we find the z-score for 1025 and find the area to the left of it in the standard normal distribution table. (c) To find the proportion of bags containing more than 1200 chips, we find the z-score for 1200 and then find the area to the right of it in the standard normal distribution table. (d) Percentile rank can be found by finding the z-score for 1425 chips, and then finding the corresponding percentile in the standard normal distribution table.
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The first and last terms of the expanded expression for the probability that at least six students will graduate in four years are:
First term:
Last term:
To find the probability that at least six students will graduate in four years, we can use the binomial probability formula.
The first and last terms of the expanded expression for this probability can be determined using the binomial coefficients.
The binomial probability formula is given by:
Where:
P(X ≥ k) is the probability that X is greater than or equal to k,
n is the number of trials (students in this case),
k is the desired number of successes (six or more students graduating),
p is the probability of success in a single trial (probability of graduating in four years).
In this case, the number of trials (n) is 10, and the probability of success (p) is 0.63.
To find the first term, we substitute k = 6 into the formula:
C(10, 6) represents the binomial coefficient, which can be calculated as:
C(10, 6) = 10! / (6! * (10 - 6)!)
To find the last term, we substitute k = 10 into the formula:
C(10, 10) = 10! / (10! * (10 - 10)!)
Hence, The first and last terms of the expanded expression for the probability that at least six students will graduate in four years are:
First term:
Last term:
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Answer:
A. 38.88
Step-by-step explanation:
$540-54 is 486
486(0.08) or 486(8%) is 38.88
Answer:
$38.88
I took the test, trust me
Answer:
1. Y
2. N
3. N
4. N
Step-by-step explanation:
Let's use the second equation, since it seems to be easier to use.
To check if an ordered pair is a solution, plug it in to the equation.
1. --> Y
2. --> N
3. --> N
4. --> N
Edit : The 4th equation doesn't work for the first equation, whereas the first one still does.
Answer:
(-2,-6)
Step-by-step explanation:
-9x +2y = 6
5x - 3y = 8
1) Make one of the coefficients the same - y.
-9x +2y = 6 * 3
5x - 3y = 8 * 3
-27x +6y = 18
10x - 6y = 16
2) Add the new equations.
(-27x +6y = 18) + (10x - 6y = 16)
(-27x +6y) + (10x - 6y) = 18 + 16
-17x = 34
3) Divide to find the value of x
-17x = 34
x = 34/-17
x = -2
4) Substitute x into either equation to find the value of y.
-9(-2) +2y = 6
18 +2y = 6
2y = -12
y = -12/2
y = -6
5(-2) - 3y = 8
-10 - 3y = 8
-3y = 18
y = 18/-3
y = -6
Your answer is (-2,-6).
3X+4Y+5X-2y+10-8
Answer:
Step-by-step explanation:
8x+2y-2