1. Two consecutive integers means that the values are whole numbers and they are located right after the other (eg. 2, 3).
Now, let us call the smaller value x. The consecutive value will be one greater than x, thus the larger value may be written as x + 1.
2. We know that the product of the two values is 420. Given that the smaller value is x and the larger value is x + 1, we can write this as:
x(x + 1) = 420
3. Now we can expand to get:
x^(2) + x = 420
4. Now subtract 420 from both sides to get:
x^(2) + x - 420 = 0
Therefor, the constant of the quadratic expression is -420.
is 13 ?
F. 10.5
G. 14.5
H. 18
J. 21.25
K. 39.5
The sum of the first 4 terms of the arithmetic sequence where the 6th term is 8 and the 10th term is 13 is 14.5.
In an arithmetic sequence, the difference between consecutive terms is constant. This difference is commonly called the common difference. Given that the 6th term is 8 and the 10th term is 13, we can calculate this common difference.
The common difference is (13 - 8) / (10 - 6) = 5 / 4 = 1.25.
The common difference is backward from the 6th term to the first term or we can say the 6th term minus 5 times the common difference will give us the first term. Therefore, the first term is 8 - 5*1.25 = 8 - 6.25 = 1.75.
The sum of the first 4 terms of an arithmetic sequence is given by the formula S = n/2 *[2a + (n-1)*d], where 'n' is the number of terms (in this case 4), 'a' is the first term, and 'd' is the common difference.
Therefore, substituting our known values into the formula gives us: S = 4/2 *[2*1.75 + (4-1)*1.25] = 2*[3.5 + 3.75] = 2*7.25 = 14.5
I believe its true but I don't really know..
Answer:
True
hope this helps