Answer:
correct answer is option C (constant)
Explanation:
Radioactive decay of radioactive element occur at known rates, the unit of radioactive decay is called half-life. The amount of time a radioactive element takes for half of the parent atoms to decay is known as half-life of a radioactive element
During Radioactive decay radioactive elements emits a particle. It's impossible to predict exactly when a given atom of a substance will emit a particular particle, but the decay rate of a radioactive element over a long period of time is constant.
By radioactive decay scientist can determine the age of that particular element. If radioactive decay will vary than age cannot be determined from radioactive decay.
In atomic emission spectroscopy, the atoms absorb energy, become excited, and release energy in the form of light.
Fe³⁺ +e⁻ -> Fe²⁺ is the half reaction equation represents the reduction of an iron(II) ion
When an element or a compound gain electron , decreasing its oxidation number is called reduced and the half cell reaction is called Reduction reaction.
Fe³⁺ +e⁻ -> Fe²⁺ , Option C
In this reaction the Iron is gaining electron and the charge is getting reduced from +3 to +2 .
Therefore this half reaction equation represents the reduction of an iron(II) ion.
To know more about Reduction Reaction
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Answer: The correct answer is Option B.
Explanation: The compound given to us is . To write the IUPAC name for this compound, we need to follow some rules:
1. First write the name of the cation with its oxidation state in roman numbers.
2. Then write the name of the anion which may be a polyatomic ion or a non-metal.
3. The anion is used with a suffix '-ide'. Example: For chlorine, the anion would be named as chloride, for sulfur, the anion would be sulfide.
For the given compound, 2 silver atoms are needed to neutralize the charge on 1 sulfur atom.
Hence, the oxidation number of silver atom is '1'. So, the IUPAC name for the compound will be silver (I) sulfide.
Therefore, the correct option is B.