The average atomic mass of oxygen is 15.9994 amu. The atomic masses of its three isotopes are as follows: O-16: 15.995 amu; O-17: 16.999 amu; O-18: 17.999 amu Which isotope is most likely to have the greatest abundance in nature?

The boiling point of standard water is 100 degree Celsius, with the addition of solute the boiling point is elevated. The freezing point of the solution will be -18.04 degree Celsius.

What is boiling point?

The boiling point is the temperature at which the liquid is converted to vapor. The change in boiling point of the aqueous solution gives the molality of the solution as:

The depression in freezing point from molality is given as;

The freezing point of aqueous water is zero degree Celsius. The freezing point of the solution will be:

The freezing point of the solution is -18.04 degree Celsius.

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Answer:

T°fussion of solution is -18°C

Explanation:

We have to involve two colligative properties to solve this. Let's imagine that the solute is non electrolytic, so i = 1

First of all, we apply boiling point elevation

ΔT = Kb . m . i

ΔT = Boiling T° of solution - Boiling T° of pure solvent

Kb =  ebuliloscopic constant

105°C - 100° = 0.512 °C kg/mol  . m . 1

5°C / 0.512 °C mol/kg = m

9.7 mol/kg = m

Now that we have the molality we can apply, the Freezing point depression.

ΔT = Kf . m . i

Kf =  cryoscopic constant

0° - (T°fussion of solution) = 1.86 °C/m  . 9.76 m . 1

- (1.86°C /m . 9.7 m) = T°fussion of solution

- 18°C = T°fussion of solution