The _____ theory is the most accepted theory regarding the origin of the solar system. It suggests that our star, the Sun, was first created by a cloud of dust and gas.

Answers

Answer 1

Answer: The Nebular Hypothesis is the most accepted explanation of the origin of our solar system. It states that the Sun was formed by a massive cloud of dust and gas light-years across, and it was bigger than the actual sun itself. Most of the mass in the center formed the sun, and the rest expanded outward.

Answer 2

Answer:

A. Nebular is the answer

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To pull a 50 kg crate across a horizontal frictionless floor, a worker applies a force of 210 N, directed 20° above the horizontal. As the crate moves 3.0 m, what work is done on the crate by (a) the worker's force, (b) the gravitational force on the crate, and (c) the normal force on the crate from the floor? (d) What is the total work done on the crate?

Answers

The work done on the crate by the worker's force is 592 J.

Given that,

Mass of the crate, m = 50kg

Force applied by the worker, F = 210N

Angle to the horizontal, θ = 20°,

Distance moved by crate, d=3m

A force causes an object with mass to change its velocity, therefore, the acceleration. acceleration caused by a force is always in the direction of force applied.

Also, we know that work done is always given as the product of force and displacement in the direction of the force.

$\bold{Work= Force* displacement}$

(a.) work done on the crate by the worker's force,

As the force is been applied at an angle directed 20° above the horizontal.

Therefore, the force is causing the crate to move in the horizontal direction, thus, only the horizontal component of the force is taken.

$\begin{aligned}W &= F\ Cos\theta * d\n&=210 * Cos (20^o)* 3\n&= 592.00\ J\n\end{aligned}$

(b) work done on the crate by the gravitational force,

$\bold{Gravitational\ force = Mass* acceleration\ due\ to\ gravity}$

As the gravitational force is always applied perpendicular to the horizontal.

Therefore, the gravitational force is not causing the crate to displace anywhere, thus, the displacement is zero.

$\begin{aligned}W &= gravitational\ force * displacement\n&=m* g * d\n&=50* 9.81* 0\n&= 0\ J\n\end{aligned}$

Hence, work done on the crate by the gravitational force is 0 J.

(c.) work done on the crate by the normal,

Normal is the contact force that is perpendicular to the surface with which the object has contact.

As the normal force did not cause the crate to displace upward by any distance.

(d.) The total work done on the crate,

As discussed above the only work done on the crate is by the worker.

Therefore, The total work done on the crate is 592 J.

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Answer:

Explanation:

Given that,

A crate of mass M = 50kg

The crate is pulled along an horizontal floor by a string at an angle

Force pulling the crate

F = 210N

Angle θ = 20° to the horizontal

Distance moved by crate d=3m

A. Work done by force

W = FdCosθ

W = 210 × 3 × Cos20

W = 592J

B. Work done by Gravitational force?

Work is define as the dot product of force and displacement in the direction of the force.

Since the gravitational force does not cause the crate to move any distance downward

Then,

W(gravity) = mg×d

distance d=0

W(gravity) = 0 J

C. Work done by normal?

Since, the normal force did not cause the crate to move upward by any distance

Then,

W(normal) = 0J

D. The total workdone?

The only workdone on the crate is by the person

Then, the total workdone is the workdone by the person

W = 592 J

If a group of workers can apply a force of 1000 newtons to move a crate 20.0 meters on a frictionless ramp: How high up a ramp will the crate travel?

Answers

That's going to depend on the mass of the crate. They'll be able to push a crate full of pingpong balls really high, but they may not be able to even budge the crate at all if it's full of bricks.

What type of image is formed by a mirror if m = -6.1? A. An image that is larger than the object and is behind the mirror
B. An image that is larger than the object and is in front of the mirror
C. An image that is smaller than the object and is in front of the mirror D. An image that is smaller than the object and is behind the mirror

Answers

B. An image that is larger than the object and is in front of the mirror

A small 175-g ball on the end of a light string is revolving uniformly on a frictionless surface in a horizontal circle of diameter 1.0 m. The ball makes 2.0 revolutions every 1.0 s. What are the magnitude and direction of the acceleration of the ball? What's the tension in the string?

Answers

Answer :

Explanation :

It is given that:

mass of the ball, $m=175\ g=0.175\ Kg$

Radius of circle, $r=(diameter)/(2)=0.5\ m$

The ball makes 2.0 revolutions every 1.0 s. So, angular speed is $\omega=4\pi\ radian/sec$

Since, it is moving in circular path so centripetal acceleration will act here.

So, centripetal acceleration $\alpha$ = $m\omega^2r$

$\alpha=0.175\ Kg* (4\pi)^2* 0.5$

So, $\alpha=13.803\ m/s^2$

Hence, the acceleration is $13.803\ m/s^2$ and it is directed towards the center of rotation.

Tension is a force which is given by :

$F=ma$

$F=0.175\ Kg*13.803\ m/s^2$

$F=2.415\ N$

This is the required answer.

For circular motion.

Centripetal acceleration = mv²/r = mω²r

Where v = linear velocity, r = radius = diameter/2 = 1/2 = 0.5m

m = mass = 175g = 0.175kg.

Angular speed, ω = Angle covered / time

   = 2 revolutions / 1 second

   = 2 * 2π radians / 1 second

   = 4π radians / second

Centripetal Acceleration = mω²r = 0.175*(4π)² * 0.5 Use a calculator

   ≈13.817 m/s²

The magnitude of acceleration ≈13.817 m/s² and it is directed towards the center of rotation.

Tension in the string = m*a

   = 0.175*13.817

   = 2.418 N

A metal plate is connected by a conductor to a ground through a switch. The switch is initially closed. A charge of +Q is brought close to the plate without touching it, and then the switch is opened. After the switch is opened, the charge +Q is removed. What is the charge on the plate then?

Answers

The charge of the plate will be negative

the positive charge will attract electrons from earth to the plate, leaving the switch opened with no return path.

The excess electron then will be trapped on the plate, causing it to be negative with respect to both earth and the charge

hope this helps

Final answer:

The metal plate will have a net positive charge of +Q. This is due to charging by induction when a +Q charge is brought near it while grounded. Opening the switch before removing the charge leaves the induced +Q charge on the plate.

Explanation:

The metal plate's charge after a

charge is brought near it, the switch is opened and the charge is removed can be explained by understanding the process of

charging by induction

and the behavior of

charge on a conductor

. When the +Q charge is brought near the metal plate, it induces a -Q charge on the plate's closest surface due to the opposite charge attraction. This leaves an equal +Q charge on the farthest surface of the metal plate, as charges inside a conductor distribute to the outer surfaces in static equilibrium. When the switch connecting the plate to ground is opened, the +Q charge on the far side of the plate can't flow to ground and remains on the plate. Removing the +Q charge after that doesn't change the plate's charge as the system is no longer closed; it is now a

net positive charge

of +Q on the metal plate.

Learn more about Charging by Induction here:

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An object moving in a circle at a constant speed is accelerating. Why?A. because it is going faster
B. because it has constant velocity
C. because its direction is changing
D. because the distance it is traveling is changing

Answers

"Acceleration" does NOT mean 'speeding up'. It means any change
in the speed or direction of motion ... speeding up, slowing down, or
moving in a curve.

An object moving in a circle at a constant speed is accelerating, because
when you're moving along a circle, your direction is constantly changing.

A. Because it is going faster.

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