Equations can be used to solve for acceleration
Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration
• An equation of uniformly accelerated motion
V = vo + at or vf = vi + at
Vt² = vo² + 2a (x-xo)
x = distance on t
vo / vi = initial speed
vt / vf = speed on t / final speed
a = acceleration
Acceleration is a change in speed within a certain time interval
a = Δv / Δ t
The velocity graph with respect to time (v-t) in this motion will be in the form of sloping straight lines with a gradient of tan θ = a
For acceleration that is positive (a> 0) is called accelerated motion, the graph is sloping upward, while for acceleration that is negative (a <0) is called slowed down motion, the graph is sloping downward
We complete the available answer choices
t = delta v over a.
vf = at - vi
a = d over t.
vi = vf - at
v = a over t.
vf = at + vi
a = delta v over t.
From the general equation of uniformly accelerated motion above, what is appropriate is:
1. t = delta v over a ---> can be used, a = v / t
2. vf = at - vi ---> cannot be used, it should be vf = vi + at
3. a = d over t .---> d = displacement has the formula: d = v x t, so this 3rd equation cannot be used
4. vi = vf - at ----> can be used
5. v = a over t ----> cannot be used, it should be v = a x t
6. vf = at + vi ---> can be used
7. a = delta v over t ----> can be used
So the equation that can be used to find acceleration is
1,4,6 and 7
The distance of the elevator
resultant velocity
the average velocity
284 rounded to the nearest hundred is 300.
Place value, which is related to a digit's location in a number, is the amount that each digit is worth.
Given:
The number is 284.
To round the number to the nearest hundred:
The digit in the hundredth place is 8.
And 8 > 4.
So, the number left to the number 2 will increase by 1.
And the number right next to 8 will become zero.
So, the value of 2 becomes 2 + 1,
and the rest number becomes zero.
So, 284 rounded to the nearest hundred is 300.
Therefore, the result is 300.
To learn more about the place value;
#SPJ2
Determine the area, in square meters, of the new rectangular garden.
15b^2 + 20b