Which equations can be used to solve for acceleration? Check all that apply.t =
vf = at – vi
a =
vi = vf – at
v =
vf = at + vi
a =

Answers

Answer 1
Answer: a =(v_f - v_i)/(t)\n\nat = v_f -v_i\n\n\boxed{\bf{v_f =at +v_i}}\n\n\boxed{\bf{v_i = v_f-at}}
Answer 2
Answer:

Equations can be used to solve for acceleration

\rm t=(\Delta v )/(a)

\rm vi=vf-at

\rm vf=at+vi

\rm a=(\Delta v )/(t)

Further explanation

Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration

• An equation of uniformly accelerated motion

\large {\boxed {\bold {x = xo + vo.t + \frac {1} {2} at ^ 2}}}

V = vo + at or vf = vi + at

Vt² = vo² + 2a (x-xo)

x = distance on t

vo / vi = initial speed

vt / vf = speed on t / final speed

a = acceleration

Acceleration is a change in speed within a certain time interval

a = Δv / Δ t

\displaystyle a = \frac {v2-v1} {t2-t1}

The velocity graph with respect to time (v-t) in this motion will be in the form of sloping straight lines with a gradient of tan θ = a

For acceleration that is positive (a> 0) is called accelerated motion, the graph is sloping upward, while for acceleration that is negative (a <0) is called slowed down motion, the graph is sloping downward

We complete the available answer choices

t = delta v over a.

vf = at - vi

a = d over t.

vi = vf - at

v = a over t.

vf = at + vi

a = delta v over t.

From the general equation of uniformly accelerated motion above, what is appropriate is:

1. t = delta v over a ---> can be used, a = v / t

2. vf = at - vi ---> cannot be used, it should be vf = vi + at

3. a = d over t .---> d = displacement has the formula: d = v x t, so this 3rd equation cannot be used

4. vi = vf - at ----> can be used

5. v = a over t ----> cannot be used, it should be v = a x t

6. vf = at + vi ---> can be used

7. a = delta v over t ----> can be used

So the equation that can be used to find acceleration is

1,4,6 and 7

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2+3x=-4(5+2x) solve for x, help please

5 ÷ 1/ 3 how do u solve

Answers

Answer: 15

You would do the Reciprocal or Multiplicative Inverse.

You can never divide by a fraction. So instead, you find the recriprocal which is pretty much just flipping the numbers and operations. So instead of dividing, we would multiply. We'd also then flip 1/3 and say its 3/1.

Now your equation is *5 x 3/1* or *5 x 3*. Thats 15.

Is 38.5 mm bigger than 10 cm?

Answers

Well, if you use KHD---DCM, or King Henry does --- dives catching mice or, Kilometers,Hectometers,Dekameters,base,Decimeters,Centimeters, Millimeters. So you see that Millimetres are after Centimeters so, 10 cm is bigger than 35.5mm

What is 284 rounded to the nearest hundred

Answers

284 rounded to the nearest hundred is 300.

What is a place value?

Place value, which is related to a digit's location in a number, is the amount that each digit is worth.

Given:

The number is 284.

To round the number to the nearest hundred:

The digit in the hundredth place is 8.

And 8 > 4.

So, the number left to the number 2 will increase by 1.

And the number right next to 8 will become zero.

So, the value of 2 becomes 2 + 1,

and the rest number becomes zero.

So, 284 rounded to the nearest hundred is 300.

Therefore, the result is 300.

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Your answer would be 300, as you can see "84" is very close to 100, making this 300

New Clarendon Park is undergoing renovations to its gardens. One garden that was originally a square is being adjusted so that one side is doubled in length, while the other side is decreased by three meters.The new rectangular garden will have an area that is 25% more that the original square garden. Write an equation that could be used to determine the length of a side of the original square garden.
Determine the area, in square meters, of the new rectangular garden.

Answers

The answer is 80 square meters.

The square area is expressed as:
A = a²,
where A is the area of the square, and a is the side of the square.

The rectangle area is expressed as:
A₁ = a₁ · b₁,
where A₁ is the area of the rectangle, and a₁ and b₁ are the sides of the rectangle.

After renovations, square garden becomes rectangular.

One side is doubled in length:
a₁ = 2a

The other side is decreased by three meters.
b₁ = a - 3

The new area is 25% than the original square garden:
A₁ = A + 25%A =
     = A + 25/100·A
     = A + 1/25·A
     = a² + 1/25·a²
     = a² + 0.25·a²
     = 1.25·a²

If the starting equation is:
A₁ = a₁ · b₁

Thus, the equation is:
1.25a² = 2a·(a - 3)
1.25a² = 2a · a - 2a · 3
1.25a² = 2a² - 6a

Therefore, the equation that could be used to determine the length of a side of the original square garden is:
2a² - 6a = 1.25a²


Now, we will solve the equation:
2a² - 6a = 1.25a²
2a² - 1.25a² - 6a = 0
0.75a² - 6a = 0
⇒ a(0.75a - 6) = 0

From here, one of the multiplier must be zero - either a or (0.75a - 6). Since a could not be zero, (0.75a - 6) is:
0.75a - 6 = 0
0.75a = 6
a = 6 ÷ 0.75
a = 8

If the side of the square is 8, then the area of the rectangle is
A₁ = 1.25 · a²
A₁ = 1.25 ·8²
A₁ = 1.25 · 64
A₁ = 80

Therefore, the area of the new rectangle garden is 80 square meters.

Factorise fully
15b^2 + 20b

Answers

15b^2+20b
5b(3b+4)

Hope this helps :)
15b^2 + 20b
=5b(3b + 4)
......................

What is the slope of the graph of 14x + 7y = –9

Answers

The slope is 0. All you had to do was put in the calculator for the right answer.