a cross-section is taken parallel to the bases of a general cylinder and has an area of 18. If the height of the cylinder is H, what is the volume of the cylinder? Explain your reasoning.
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Answer 1
Answer:
∵ the cross-section is parallel to the bases of the cylinder, then it is congruent to the bases thus, the area of the base of the cylinder is 18. The volume of a general cylinder is the product of the area of the cylinder’s base times the height of the cylinder, So the volume of the general cylinder is = 18 H
ALGEBRA HELP, please help with problem, and show work
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First of all, your second term is already wrong. When you divided 8x² by 4 , you should have written 2x² , not 4x² .
Make that correction, and then divide the whole thing by 'x'.
Then you'll have x² - 2x + 1 = 0 .
You should have no trouble solving that one, (especially since it's a perfect square)
That gives you two (equal) solutions. But you should also ask yourself: "Self ! Where is the third solution ? A cubic equation like the original one needs three solutions."
I'll give you that one: Look over the original equation, and look at what happens to it when x = 0 . Then the left side becomes zero, and the equation is 0 = 0 . Since that's a true statement, " x = 0 " is another solution of the cubic equation, and now you have all three of them.
divide both sides by 4x: x^2-2x+1=0 You can either factor, complete the square, or use the quadratic formula. I'll factor this into (x-1)(x-1)=0 x-1=0, so x=1
Sins = 8x2 and = 2x + a find 5- o
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(f × g ) (w) (Please note that I have used w in place of x) ∴((8w²) × (2w+8) × w (16w³ × 64w²) × w × 64w³
terrence finished a word search in 3/4 the time it took frank. charlotte finished the word search in2/3 the time it took terrence.frank finished the word search in 32 min. how long did it take charlotte to finish the word search
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yeah i think the answer could be ;
2/3 of the time it took Terrence to finish the word search
time for Terrence; 3/4*32 = 24 min
time for Charlotte; 2/3*24= 16 min
therefore it took Charlotte 16 min to finish the word.....thx
What is 1 tenth of 0.65??
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0.065 thats the answer
ΔABC will undergo two transformations to give ΔA′B′C′. Which pair of transformations will give a different image of ΔABC if the order of the transformations is reversed?
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a rotation 90° counterclockwise about the origin followed by a reflection across the y-axis