I will make u the BRAINLIEST pls answer my question and explain!!!
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Since the problem tells you the length of each square is 1 ft, then you know that the distance between the two plants is 10 squares * 1 ft/square = 10ft.
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Answer:
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Answer:
it's me again. Is the answer B?
Step-by-step explanation:
2(3x - 2)(x - 2) = 0
2(6x - 4)(x - 1) = 0
2(x - 1)(3x - 4) = 0
Answers
2(3x^2 - 7x + 4) = 0
2(3x^2 - 3x - 4x + 4) = 0
2(3x(x - 1) - 4(x - 1)) = 0
2(x - 1)(3x - 4) = 0
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9 x 9 = 81
27+81= 109
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Answer:
(a) The inequality for the number of items, x, produced by the labor, is given as follows;
250 ≤ x ≤ 600
(b) The inequality for the cost, C is $1,000 ≤ C ≤ $3,000
Step-by-step explanation:
The total time available for production = 1000 hours per week
The time it takes to produce an item on line A = 1 hour
The time it takes to produce an item on line B = 4 hour
Therefore, with both lines working simultaneously, the time it takes to produce 5 items = 4 hours
The number of items produced per the weekly labor = 1000/4 × 5 = 1,250 items
The minimum number of items that can be produced is when only line B is working which produces 1 item per 4 hours, with the weekly number of items = 1000/4 × 1 = 250 items
Therefore, the number of items, x, produced per week with the available labor is given as follows;
250 ≤ x ≤ 1250
Which is revised to 250 ≤ x ≤ 600 as shown in the following answer
(b) The cost of producing a single item on line A = $5
The cost of producing a single item on line B = $4
The total available amount for operating cost = $3,000
Therefore, given that we can have either one item each from lines A and B with a total possible item
When the minimum number of possible items is produced by line B, we have;
Cost = 250 × 4 = $1,000
When the maximum number of items possible, 1,250, is produced, whereby we have 250 items produced from line B and 1,000 items produced from line A, the total cost becomes;
Total cost = 250 × 4 + 1000 × 5 = 6,000
Whereby available weekly outlay = $3000, the maximum that can be produced from line A alone is therefore;
$3,000/$5 = 600 items = The maximum number of items that can be produced
The inequality for the cost, C, becomes;
$1,000 ≤ C ≤ $3,000
The time to produce the maximum 600 items on line A alone is given as follows;
1 hour/item × 600 items = 600 hours
The inequality for the number of items, x, produced by the labor, is therefore, given as follows;
250 ≤ x ≤ 600
(a) The inequality for the number of items, x, produced by the labor, is given as follows;
250 ≤ x ≤ 600
(b) The inequality for the cost, C is $1,000 ≤ C ≤ $3,000
What is inequality?
Inequality is a statement shows greater the, greater then equal to, less then,less then equal to between two algebraic expressions.
The total time available for production = 1000 hours per week
The time it takes to produce an item on line A = 1 hour
The time it takes to produce an item on line B = 4 hour
Therefore, with both lines working simultaneously, the time it takes to produce 5 items = 4 hours
The number of items produced per the weekly labor = 1000/4 × 5 = 1,250 items
The minimum number of items that can be produced is when only line B is working which produces 1 item per 4 hours, with the weekly number of items = 1000/4 × 1 = 250 items
Therefore, the number of items, x, produced per week with the available labor is given as follows;
250 ≤ x ≤ 1250
Which is revised to 250 ≤ x ≤ 600 as shown in the following answer
(b) The cost of producing a single item on line A = $5
The cost of producing a single item on line B = $4
The total available amount for operating cost = $3,000
Therefore, given that we can have either one item each from lines A and B with a total possible item
When the minimum number of possible items is produced by line B, we have;
Cost = 250 × 4 = $1,000
When the maximum number of items possible, 1,250, is produced, whereby we have 250 items produced from line B and 1,000 items produced from line A, the total cost becomes;
Total cost = 250 × 4 + 1000 × 5 = 6,000
Whereby available weekly outlay = $3000, the maximum that can be produced from line A alone is therefore;
$3,000/$5 = 600 items = The maximum number of items that can be produced
The inequality for the cost, C, becomes;
$1,000 ≤ C ≤ $3,000
The time to produce the maximum 600 items on line A alone is given as follows;
1 hour/item × 600 items = 600 hours
The inequality for the number of items, x, produced by the labor, is therefore, given as follows;
250 ≤ x ≤ 600
Hence the inequality for the number of items, x, produced by the labor, is 250 ≤ x ≤ 600 and the inequality for the cost, C is $1,000 ≤ C ≤ $3,000
To know more about Inequality follow
Answers
Considering that we already are given the length of the floor we must divide 100 (the area) by 10 (the length) to get the width
100/10= 10 (the width)
The perimeter is equal to each side of the rectangle added together, a rectangle has two lengths and two widths
Therefore: 10 (the length) + 10 (the length) + 10 (the width) + 10 (the width) = 40
The perimeter is 40 feet
Answers
-6x = -9
x = 1,5