The question given above is not complete, the options attached to the question is given below:
A). Putting them in a deep pool of water
B). Burying them in a deep underground storage facility
C). Sending them on the shuttle to be suspended in space
D). Putting them in concrete/lead casks and sitting at thereactor site
ANSWER
The correct option is C.
There are many ways of storing spent nuclear fuel rods, these include: immersing them in deep pool of water, storing them in lead casks and burying them in deep underground storage. These forms of storage are utilized in order to protect people and the environment from the harmful radiations that radiate from these fuel rods. Spent fuel rods must never be exposed, therefore it is not possible to suspend them in space.
Answer:
c
Explanation:
Answer:
Carbonic acid
Best of luck
it tends to be more negative across a period
it tends to remain the same across periods
it tends to be more negative down a group
The answer is it tends to be more negative down a group. This is because as you go down the periodic table, the elements have more electron shells in their atoms. This makes the outermost shells less attracted to the nucleus due to their greater distances from the nucleus. Therefore, these shells are less likely to attract electrons (hence lower electron affinity) and are even more likely to lose electrons from their outer electron orbits.
Answer:
it tends to be more negative across a period
Explanation:
We have to remember that the periodic table is arranged accordingly to the number of electrons that the elements have in their outer valance shell, so the closer you are to the right of the periodic table the closer you get to the elements taht have the most electrons in their outer valance shells, this means that they have a greater negative electron affinity, which means that the elements on the right are more willing to gain an electron.
to solve the amount of sulfuric acid to maximize the profitwe need to establish the profit
let S(x) = 100x the selling price
P = S(x) – C(x)
P = 100x – ( 100,000 + 50x + 0.0025x^2)
P = 50x – 100000 – 0.0025x^2
Getting the first derivative and equating it to 0
0 = 50 – 0.005x
X = 10000 units of sulfuric acid
But the capacity is only 7000 units
So 7000 units should be manufactured