don't know what to do so please help
Answer:
see explanation
Step-by-step explanation:
This is a quadratic equation
Rearrange into standard form : ax² + bx + c = 0 : a ≠ 0
subtract 20e from both sides
25e² - 20e + 4 = 0 ← in standard form
This is a perfect square of the form
(a - b)² = a² - 2ab + b²
25e² = (5e)² ⇒ a = 5e and 4 = 2² ⇒ b = 2, and
- 2ab = - 2 × 5e × 2 = - 20e, hence
25e² - 20e + 4 = (5e - 2)²
⇒ (5e - 2)² = 0 ⇒ e = with multiplicity 2
Answer:
3
Step-by-step explanation:
Answer:
B. 2x + 3 ≥ 11 or 4x - 7 ≤ 1
Step-by-step explanation:
Given compound inequality,
In option A,
2x + 3 ≥ 11 and 4x - 7 ≤ 1
⇒ 2x ≥ 8 and 4x ≤ 8
⇒ x ≥ 4 and x ≤ 2
2x + 3 ≥ 11 and 4x - 7 ≤ 1 can not be the correct inequality,
In option B,
2x + 3 ≥ 11 or 4x - 7 ≤ 1
⇒ 2x ≥ 8 or 4x ≤ 8
⇒ x ≥ 4 or x ≤ 2
Which is shown in the given graph,
Thus, 2x + 3 ≥ 11 or 4x - 7 ≤ 1 is the correct compound inequality,
In option C,
2x + 3 > 11 or 4x - 7 < 1
⇒ 2x > 8 or 4x < 8
⇒ x > 4 or x < 2
So, which is not shown in the graph,
2x + 3 > 11 or 4x - 7 < 1 can not be the correct compound inequality,
In option D,
2x + 3 ≥ 11 or 4x - 7 ≥ 1
⇒ 2x ≥ 8 or 4x ≥ 8
⇒ x ≥ 4 or x ≥ 2
Which is not shown in the graph,
2x + 3 ≥ 11 or 4x - 7 ≥ 1 is not the correct compound inequality.
B.. 4 is less than or equal to x, 2 is greater or equal to x