The answer to 3 problems 1/4 foot= how many inches. 3/4 year = how many months. 3/5 meter= how many centimeters.

Answers

Answer 1

Answer: 1/4 foot = how many inches ⇒ 3 inches
3/4 year = how many months ⇒ 9 months
3/5 meter = how many centimeter ⇒ 60 cm

1 foot has 12 inches.

1/4 foot * 12inches/1foot = 12inches/4 = 3 inches.

1 year has 12 months

3/4 year * 12 months/1year = (3*12)/4 = 36/4 = 9 months

1 meter has 100 centimeter

3/5 meter * 100 cm/1m = (3*100cm)/5 = 300/5 = 60 centimeters.

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How do I find the correct variable for N? (It won't be negative I think)

Answers

Answer:

$25$

Step-by-step explanation:

$\mathrm{For\ the\ set\ to\ be\ the\ sets\ of\ natural\ numbers,\ (n)/(5)\ and\ √(n+144)\ must\ be\ a}\n\mathrm{positive\ integer.}\n\mathrm{√(n+144)\ is\ a\ natural\ number\ when\ (n+144)\ is\ a\ perfect\ square.}\n\mathrm{And\ (n)/(5)\ is\ a\ natural\ number\ if\ and\ only\ if\ n\ is\ exactly\ divisible\ by\ 5.}\n\mathrm{So\ we\ need\ to\ find\ the\ smallest\ positive\ integer\ which\ would\ make\ both\ of\ these}\n\mathrm{cases\ true.}$

$\mathrm{Now\ we\ know\ that\ 144\ is\ a\ perfect\ square.\ The\ most\ closed\ perfect\ square\ to}\n\mathrm{144\ are\ 121\ and\ 169.}\n\mathrm{We\ are\ taking\ these\ closest\ perfect\ squares\ to\ 144\ because\ we\ want\ the\ value\ of}\n\mathrm{n\ to\ be\ as\ small\ as\ possible.}\n\mathrm{Now\ if\ (n+144)=121,\ n=23\ (which\ is\ not\ divisible\ by\ 5).}\n\mathrm{if\ (n+144)=169,\ n=25(which\ is\ divisible\ by\ 5).}$

$\mathrm{Notice,\ when\ n=25,\ 34+n,\ (n)/(5)\ and\ √(n+144)\ are\ all\ natural\ numbers.}\n\therefore\ \mathrm{n}=25.$

What is the range of each function given below?
a. Let f(x) = 9x − 1.

Answers

Answer:

Range of f=R

Step-by-step explanation:

We are given that a function

$f(x)=9x-1$

We have to find the range of given function.

The given function is linear function because the degree of function is 1.

When the degree of function is 1 then the function is called the linear function.

The domain of linear function is a set of real numbers because it can be defined for all real values of x.

Domain of given function =R

When we substitute the real value of x in given function then we get a real number also.

Therefore, the range of f=R

The legs of an isosceles triangle are 0.3 foot less than twice the base. The perimeter of the triangle is 4.9 feet.What is the length of one of the triangle’s legs?

Answers

The length of one of the triangle’s legs is 1.9 ft.

What is an isosceles triangle?

An isosceles triangle is a triangle having two sides of equal length.

Given that, The legs of an isosceles triangle are 0.3 foot less than twice the base. The perimeter of the triangle is 4.9 feet.

Base = b

Length = 2b-0.3

Perimeter = b+2b-0.3+2b-0.3

4.9 = 5b-0.6

5b = 5.5

b = 1.1

Length =2×1.1-0.3

= 2.2-0.3

= 1.9

Hence, The length of one of the triangle’s legs is 1.9 ft.

For more references on isosceles triangle, click;

brainly.com/question/2456591

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I hope this helps you

base = b

length= 2b-0.3

Perimeter=b+2b-0.3+2b-0.3

4.9=5b-0.6

5b=5.5

b=1.1

length =2×1.1-0.3

length=2.2-0.3

length=1.9

Give away say thank you
first gets the brain

Answers

Answer: THANK U (:

Step-by-step explanation:

Answer:

thanks? srry im a lil late

Step-by-step explanation:

Prove that

(1 + cot A + tan A) (sin A - cos A) = sin A tan A - cot A cos A

Answers

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

tan A = $(sinA)/(cosA)$ , cot A = $(cosA)/(sinA)$

Consider the left side

(1 + cotA + tanA)(sinA - cosA)

each term in the second factor is multiplied by each term in the first factor.

1(sinA - cosA) + cotA(sinA - cosA) + tanA(sinA - cosA)

= sinA - cosA + cosA - $(cos^2A)/(sinA)$ + $(sin^2A)/(cosA)$ - sinA ( collect like terms )

= $(sin^2A)/(cosA)$ - $(cos^2A)/(sinA)$

= ( sinA × $(sinA)/(cosA)$ ) - ( $(cosA)/(sinA)$ × cosA )

= sinAtanA - cotAcosA

= right side ⇒ proven

When graphed, which of the following is the solution of the given system below?-3=-y-4x

0=6-2y-8x

a.(2,-5)

b. (1,2)

c. (2,-2)

d. Infinite number of solutions