Y − x = -13 -4x + 3y = -51

Answers

Answer 1

Answer: y - x = -13
-4x + 3y = -51

Use any of the equation to find the value of x or y. In this case, I'll use the 1st equation to find the value of y.

y - x = -13
y = x - 13

Substitute the value of y in the 2nd equation to find the value of x.

-14x + 3y = -51
-14x + 3(x-13) = -51
-14x + 3x - 39 = -51
-11x = -51 + 39
-11x = -12
x = 12/11 or 1 1/11

Substitute the value of x in any equation to find the value of y.

y = x - 13
y = 12/11 - 13
y = 12/11 - (13*11/11) *to get the common denominator
y = (12 - 143)/11 = -131/11 = 11 10/11

to check: x = 12/11 or 1 1/11 ; y = -131/11 or 11 10/11

y - x = -13
-131/11 - 12/11 = -13
(-131 - 12)/11 = -13
-143/11 = -13
-13 = -13

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Destiny performs a hypothesis test on a population with µ = 115 and mc009-1.jpg. Her sample size is 25 with a mean of 120.4. Which of the following correctly depicts the z-statistic for this data?

Answers

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Answer:

the answer is b. 0.90

2.4 - |-3.61| - (-8.3)

Answers

2.4-|-3.61|-(-8.3)
2.4-3.61-(-8.3)
-1.21-(-8.3)
7.09

2.4 -3.61 +8.3hence answer is 7.0900

7. Find the value of x for which € || m.(1 point)
(x + 25)
30
35
55
80

Answers

Answer:

x = 30

Step-by-step explanation:

Corresponding angles are congruent where a transversal crosses parallel lines.

55 = x +25

30 = x . . . . . . . subtract 25

Graph the image of this figure after a dilation with a scale factor of 1/3 centered at the origin.Use the polygon tool to graph the dilated figure.

Answers

Answer:

see attached diagram

Step-by-step explanation:

A dilation with a scale factor of $(1)/(3)$ centered at the origin has a rule:

$(x,y)\mapsto\left((x)/(3),(y)/(3)\right).$

Then the image of the triangle ABC is triangle DEF(see attached diagram) with coordinates

$D\left((-3)/(3),(3)/(3)\right)\Rightarrow D(-1,1);$
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How to solve number 21 :/

Answers

$\left(\begin{array}{cc}1&1\n-2&1\end{array}\right) \bold{M}= 2\left(\begin{array}{cc}1&0\n0&1\end{array}\right)\n \bold{M}=2\frac{ \left(\begin{array}{cc}1&0\n0&1\end{array}\right) }{ \left(\begin{array}{cc}1&1\n-2&1\end{array}\right)}\n \bold{M}=2\left(\begin{array}{cc}1&0\n0&1\end{array}\right) \left(\begin{array}{cc}1&1\n-2&1\end{array}\right)^(-1)$

$\left(\begin{array}{cc}1&1\n-2&1\end{array}\right)^(-1)=(1)/(1-(-2))\left(\begin{array}{cc}1&-1\n2&1\end{array}\right)\n\left(\begin{array}{cc}1&1\n-2&1\end{array}\right)^(-1)=(1)/(3)\left(\begin{array}{cc}1&-1\n2&1\end{array}\right)\n\left(\begin{array}{cc}1&1\n-2&1\end{array}\right)^(-1)=\left(\begin{array}{cc}(1)/(3)&-(1)/(3)\n(2)/(3)&(1)/(3)\end{array}\right)\n\n$
$\bold{M}= 2\left(\begin{array}{cc}1&0\n0&1\end{array}\right)\left(\begin{array}{cc}(1)/(3)&-(1)/(3)\n(2)/(3)&(1)/(3)\end{array}\right)\n\bold{M}= 2\left(\begin{array}{cc}(1)/(3)&-(1)/(3)\n(2)/(3)&(1)/(3)\end{array}\right)\n\bold{M}= \left(\begin{array}{cc}(2)/(3)&-(2)/(3)\n(4)/(3)&(2)/(3)\end{array}\right)$

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Answers

frist 5 in / 1 over 2 = 2.5

So yes she can do that

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