y 5 10 15 20
A.
1
B.
2
C.
3
D.
5
Answer:
Option D - 5
Step-by-step explanation:
Given : Table
x 1 2 3 4
y 5 10 15 20
To find : The constant of variation for the relationship shown in the following table?
Solution :
The constant of variation means the relationship between variables does not change.
The constant of variation for an equation is , where k is the constant of variation.
Now, We have given the value of x and y substitute in the formula,
x=1,y=5
x=2,y=10
x=3,y=15
x=4,y=20
Therefore, The constant of variation is 5.
So, Option D is correct.
X squared + 5x -6
X squared - 2x15
X squared -7x +12
Answer:
Step-by-step explanation:
In each case, you're looking for divisors of the constant that have a sum equal to the x-coefficient. Those divisors are the constants in the binomial factors.
1) -6 = -1·6 = -2·3 . . . . . (-1)+(6) = 5, so these are the constants of interest.
x^2 +5x -6 = (x -1)(x +6)
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2) -15 = -1·15 = -3·5 = -5·3 . . . . . (-5)+(3) = -2, so these are the constants of interest
x^2 -2x -15 = (x -5)(x +3)
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3) 12 = -1·-12 = -2·-6 = -3·-4 . . . . . (-3) +(-4) = -7, so these are the constants of interest
x^2 -7x +12 = (x -3)(x -4)
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