Answer: is neither an acid nor a base
Explanation: Water is a universal solvent which means it can dissolve most of the substances in it.
Water has high thermal heat capacity , which means large heat is required to heat the water.
Water is not always pure as it gets contaminated by various pollutants present in the atmosphere such as gases, bacteria and suspended matter.
Water is an amphoteric substance which can act as both acid and base, thus can donate and acept [texH^+[/tex] ions.Thus it is neither an acid nor a base.
Here water is accepting a proton, thus it acts as base.
Here water is donating a proton, thus it acts as acid.
Answer:
Is neither an acid nor a base
Explanation:
Answer: 484.94 K
Explanation:
T2 = T1 X V2 / V1
Temperature must be in kelvin so 543 + 273.15 =816.15
816.15 X 51.1 / 86
Answer: We can use the combined gas law to solve this problem:
(P₁V₁/T₁) = (P₂V₂/T₂)
where P is pressure, V is volume, and T is temperature in Kelvin.
We know that P₁ = P₂ (the pressure is assumed to be constant), and we are given V₁, T₁, and V₂. We can solve for T₂:
(P₁V₁/T₁) = (P₂V₂/T₂)
T₂ = (P₂V₂/T₁) * (T₁/P₁V₁)
We need to convert the initial temperature from Celsius to Kelvin:
T₁ = 543 + 273 = 816 K
Substituting the values:
T₂ = (1 atm * 86 mL / 816 K) * (51.1 mL / 1 atm * 86 mL)
T₂ = 0.0629 * 51.1 * 1000 = 3217 K
Therefore, the marshmallow would need to be heated to a temperature of 3217 K for its volume to change from 86 mL to 51.1 mL.
Enjoy (:
(1) 46 g (3) 85 g
(2) 61 g (4) 126 g
The answer is 46 g
The explanation :
According to the attached curve of the relation between the temperature and the grams in solutions:
-we can see from the curve that the grams of NaNO3 at 60°C = 126 g
-and the grams of NaNO3 at 10°C = 80 g
-so, To get the grams of NaNO3 settled out of the original solution, we will subtract the grams of NaNO3 at 10°C - the grams of NaNO3 at 60°C
126 g - 80 g = 46 g
∴ the correct answer is 46 g
Answer: 2Na + 2H₂O → 2NaOH + H₂
According to the equation, 2 moles of Na react with 2 moles of H₂O to produce 1 mole of H₂ gas.
To calculate the number of moles of Na in 120 g, we need to know the molar mass of Na, which is 22.99 g/mol. We can set up a conversion factor:
120 g Na * (1 mol Na / 22.99 g Na) = 5.22 mol Na
Since the reaction ratio is 2 moles of Na to 1 mole of H₂, we can set up another conversion factor:
5.22 mol Na * (1 mol H₂ / 2 mol Na) = 2.61 mol H₂
Now, to convert moles of H₂ to grams of H₂, we need to know the molar mass of H₂, which is 2.02 g/mol. Again, we set up a conversion factor:
2.61 mol H₂ * (2.02 g H₂ / 1 mol H₂) = 5.27 g H₂
Therefore, when 120 g of Na reacts with water, approximately 5.27 grams of hydrogen gas will be produced.
Note: Remember to round your final answer to an appropriate number of significant figures based on the given data.
Explanation:
To find the grams of hydrogen produced, we need to calculate the moles of Na, determine the moles of H2O using the mole ratio, and convert the moles of H2 to grams.
To determine how many grams of hydrogen are produced when 120 g of Na is available, we first need to calculate the moles of Na using its molar mass. Then, we use the balanced chemical equation to determine the mole ratio between Na and H₂O. Finally, we convert the moles of H₂ to grams. Here are the steps:
1. Calculate the moles of Na:
moles of Na = (mass of Na) / (molar mass of Na)
2. Determine the moles of H₂O using the mole ratio:
moles of H₂O = (moles of Na) x (moles of H₂O / moles of Na)
3. Convert the moles of H₂ to grams:
grams of H₂ = (moles of H₂) x (molar mass of H₂)
Using these steps and the given values, we can calculate the grams of hydrogen produced from 120 g of Na.
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The correct student is Student D, who says that Fluorine (F) has the highest ionization energy because the smaller the atom, the stronger the attraction between protons and valence electrons.
The stronger the attraction, the more energy is needed to remove a valence electron.
Ionization energy refers to the energy required to remove an electron from an atom. Smaller atoms have a stronger attraction between the positively charged protons in the nucleus and the negatively charged electrons in the outermost energy level. As a result, it takes more energy to remove an electron from a smaller atom like fluorine. This is because the electrons are held more tightly due to the stronger attraction.
So, the reasoning provided by Student D correctly explains why Fluorine has the highest ionization energy among Selenium (Se) and Fluorine (F).
Learn more about ionization energy from the link given below.
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I think the Answer is C because Flourine is stronger in electron attraction and is smaller so it has a stronger electronic pull. Hope this helps :)