B. 22 Hz and 42 Hz
C. 47 Hz and 55 Hz
D. 18 Hz and 26 Hz
Answer:
B. 22 Hz and 42 Hz
Explanation:
The beat is an interference pattern which occurs when two waves of slightly different frequencies meet each other. The beat is heard as a periodic variation, whose frequency (called beat frequency) is equal to the absolute value of the difference between the frequencies of the individual waves:
In this problem, we are told that 20 beats per second are produced, so the beat frequency is
Therefore, we must find the two waves which have a difference in frequency equal to this value, 20 Hz. Let's see each choice:
A. 38 Hz and 63 Hz --> --> NO
B. 22 Hz and 42 Hz --> --> YES
C. 47 Hz and 55 Hz --> --> NO
D. 18 Hz and 26 Hz --> --> NO
So, the correct choice is
B. 22 Hz and 42 Hz
If a traveler first drives 18.6 km east, then 30.3 km southeast, and finally 10.7 km south then the traveler's total displacement would be 51.30 kilometers.
An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard. Displacement describes this shift in location.
As given in the problem If a traveler first drives 18.6 km east, then 30.3 km southeast, and finally 10.7 km south then we have to find the traveler's total displacement,
the total displacement in the east direction = 18.6 + 30.3Cos45°
the total displacement in the east direction = 40 km
the total displacement in the south direction = 10.7 + 30.3Cos45°
the total displacement in the south direction = 32.12 km
The net resultant displacement = √(40² + 32.12²)
The net resultant displacement = 51.30 kilometers
Thus, the traveler's total displacement comes out to be 51.30 kilometers.
Learn more about displacement here, refer to the link;
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Answer:
air speed
Explanation:
took the exam
Answer:
The highlight