S (-5k +20)
13
Answer:
- 10
Step-by-step explanation:
Substitute k = 3, 4, 5, 6 into the expression and sum the terms, that is
(- 15 + 20) + (- 20 + 20) + (- 25 + 20) + (- 30 + 20)
= 5 + 0 - 5 - 10
= - 10
Answer: 46
Step-by-step explanation: 2 7/8 divided by 1/16= 46
Branly pls
Answer:
Step-by-step explanation:
2 7/8 divided by 1/16
= 2 7/8 ÷ 1/16
= 23/8 ÷ 1/16
= 23/8 × 16/1
= 23 × 2
= 46
Answer:
4.75x + 3.75y ≤ 15 inequality models the given situation.
Harper can buy at maximum 3 bags of fruits.
Step-by-step explanation:
Given : Harper has $15.00 to spend at the grocery store. She is going to buy bags of fruit that cost $4.75 each and one box of crackers that costs $3.50.
We have to write and solve an inequality that models this situation and could be used to determine the maximum number of bags of fruit that Harper can buy.
Let Harper buys 'x' bags of fruit
and 'y' box of crackers
Given : cost of one bags of fruits is $ 4.75
so the cost of x bags of fruits is 4.75x
Given : cost of one box of cracker is $ 3.50
so the cost of y box of crackers is 3.75y
also, Harper has $15.00 to spend at the grocery store
So the maximum amount he can spend is $15
So inequality become,
4.75x + 3.75y ≤ 15
So the maximum number of bags of fruit Harper can buy.
is when he buys no box of cracker.
Put y = 0 in above inequality , we have,
4.75x + 3.75(0) ≤ 15
4.75x ≤ 15
Divide both side by 4.75
We have , x = 3.158 ≈ 3
So , Harper can buy at maximum 3 bags of fruits.
twice as many dimes as quarters. How
many of each coin are in the purse?
Answer:
dimes = 12, quarters =5
Step-by-step explanation:
Let x stand for quarters. So if there are two more than twice as many dimes than quarters than it would look something like
d = 2x+2
q = x
Now multiply them by the value of the coin, to get them into cents. So you'd multiply dimes by twn (2x+2*10) which is equal to 20x+20. Multiply quarters by 25. x*25=25x
Now make an equation. 20x+20+25x=245
45x=225
x=5
q = 5
d = 12