What two numbers add to equal 11 and multiply to equal 10

Answers

Answer 1
Answer: Hi There! The answer is 10 and 1. Because you add 10 and 1 to get 11 and 10 times 1 equals 10. Hope this helps.

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Write 63 as a sum of tens and ones

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The sum of 6+3 (63) = 9.

Round 118.380 to the nearest hundredths

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The number in the hundredths place is 3, so look to the number at the right of 3. If it is equal to or above 5, you would have to round the number in the hundredths place to one number higher. Because 8 is above 5, you would round 3 to 4.

118.380 rounded to 118.4 is your answer

Hope this helps :)

Please help!!!!!!!!!!!!

Answers

Answer:

yes they are inverserve of each other  

Step-by-step explanation:

f(x) = y just for say

y=3x+9

switch the x and y value and solve for y

x=3y+9

x-9=3y

(x-9)/3 = y

inverserve of f(x) is g(X)

and now g(x) = y

y= (x-9)/3

switch x and y and solve for y

x=(y-9)/3

3x= y-9

3x+ 9 = y

inverserve of g(x) is f(X)

Use properties to find the sum or product 5×23×2

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You go from left to right; so, 5 x 23 is 115, bring the x2 down and multiply 2 by 115, and you get 230.

give an example of addition problem in which you would and would not group the addends differently to add

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In a problem like 1+1+1, I would not group the addends differently. This is because, no matter which way you place the ones, you will always be adding 1+1+1.

In a problem like 3+5+7, I would group the addends differently (3+7+5). This is because, in the first problem you would first add together 3+5 to get 8, and then you would add 8+7 to get 15. However, if you were to add 3+7 first, you would get 10. 10+5 is much easier to add than 8+7.
An example of a problem where I would not group the addends differently is:

3+2+4.

An example of a problem where I would group the addends differently is:

2+5+8.

Explanation:

In the first problem, I would not group the addends differently before adding.  This is because I cannot make 5 or 10 out of any of the numbers.  We group addends together to make "easier" numbers for us to add, such as 5 and 10.  If we cannot do that, there is no reason to regroup the addends.

In the second problem, I would regroup like this:
2+8+5

This is because 2+8=10, which makes the problem "easier" for us to add.  Since we can get a number like this that shortens the process, we can regroup the addends.

What number can go into 39 and 52

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39 divided 13 is 3
52 divided 13 is 4
Therefore, the answer is 13