How do you work out the interquartile range?
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Please answer as soon as possible
suppose the equation for line A is given by 2x-5y=15, if line A and B are parallel and the point (-10,3) lies on line B, then write the equation in slope intercept for line b.
If a line contains the point (0, -1) and has a slope of 2, then which of the following points also lies on the line?(2, 1) (1, 1) (0, 1)
Convert 0.0049 as a decimal fraction
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Answer:
HERE
Step-by-step explanation:
To determine which system has x = 3 and y = 2.5 as its solution, we need to substitute these values into each system of equations and check which one satisfies the conditions.
System 1: 7x - 5y = 33.5
Substituting x = 3 and y = 2.5:
7(3) - 5(2.5) = 21 - 12.5 = 8.5
System 2: 3x + 3y = 1.5
Substituting x = 3 and y = 2.5:
3(3) + 3(2.5) = 9 + 7.5 = 16.5
System 3: 4x + y = 9.5
Substituting x = 3 and y = 2.5:
4(3) + 2.5 = 12 + 2.5 = 14.5
System 4: 5x - y = 12.5
Substituting x = 3 and y = 2.5:
5(3) - 2.5 = 15 - 2.5 = 12.5
System 5: 2x - 5y = 18.5
Substituting x = 3 and y = 2.5:
2(3) - 5(2.5) = 6 - 12.5 = -6.5
System 6: x + y = 5.5
Substituting x = 3 and y = 2.5:
3 + 2.5 = 5.5
System 7: 11x + 10y = 8
Substituting x = 3 and y = 2.5:
11(3) + 10(2.5) = 33 + 25 = 58
System 8: 5x - 2y = -20
Substituting x = 3 and y = 2.5:
5(3) - 2(2.5) = 15 - 5 = 10
From the calculations, we can see that only System 4: 5x - y = 12.5 satisfies the given conditions when x = 3 and y = 2.5. Therefore, the correct answer is System 4.
Round your answer to the nearest tenth.
HELP PLEASE
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The required 6 kilometers in miles is given as 3.6 miles.
Given that,
To Value of 6 kilometers in miles is to be determined.
What is simplification?
The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.
Here,
1 km = 0.6 mi,
multiply both sides by 6
6 km = 3.6 mi
Thus, the required 6 kilometers in miles is given as 3.6 miles.
Learn more about simplification here:
#SPJ1
±square root of 20
±5
±20
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Answer:
x = ±√10
Step-by-step explanation:
Don't you mean x^2 = 10 or x² = 10?
Taking the square root of both sides, we get:
x = ±√10 (matches first answer)
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So,
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Answer:
The stopping distance for a car traveling 40 mph is 240 feet.
Step-by-step explanation:
We are given the following in the question:
The stopping distance (s) of a car varies directly as the square of its speed (v)
Removing the sign of proportionality and adding constant of proportionality, we get
where k is constant of proportionality.
Now, when s = 60 feet, v = 20 mph
Putting values, we get,
Putting value of k in the equation, we get,
We have to find the stopping distance for a car traveling 40 mph.
Thus, the stopping distance for a car traveling 40 mph is 240 feet.
x = 1/8log2
x= 5/8
x =log5/8
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2^(8x)-3=7
==>2^(8x)=10
==>8x log (2)=log(10)
==>8x log(2)=1
==>x=1/(8*log(2))
With parenthesis on the denominator, the answer is B.