The increase in velocity for the car, given an average acceleration of 12 m/s² over 4.0 seconds, can be calculated as 48 m/s.
The question asks to calculate the increase in velocity of a car given an average acceleration of 12 m/s² over a time span of 4.0 seconds. This is a straightforward application of the formula for acceleration, which is defined as the change in velocity per unit of time. Hence, we can rearrange this formula to find the change in velocity, which is also known as 'delta v': Delta v (change in velocity) = Acceleration * Time. Substituting our given values, we find: Delta v = 12 m/s² * 4.0 s = 48 m/s.
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Answer:
Step-by-step explanation:
ima say 6
xy^5-x^4y
Help plsss
Answer:
Step-by-step explanation:
Given that,
xy^5-x⁴y
First we look for what is common, so x and y are common to both expression
So, let bring xy out
xy(y⁴-x³).
Answer:
50.2
Step-by-step explanation:
202/4=50.2