Round .0091 to the thousandths

Answers

Answer 1
Answer: The answer is 0.009.
Hope this helps!:)
Answer 2
Answer: 0.0091 rounded to the nearest thousandths would be 0.009. This is because the 1 after the 9 is BEFORE 5 so it stays as 9, and we remove the 1. 

Answer:- .0091 rounded to the nearest thousandths is .009.

Hope I helped ya!! xD


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What is 22/11 when simplified and how did you solve that?

Answers

22/11
= (22/11) / (11/11)
= 2/1
= 2

The final answer is 2~
If 11/11 were to be equal to 1, then 22/11 will be equal to 2.

A bookstore charges a standard rate for paperback or hardback books. The cost of a paperback book is 11 dollars less than the cost of a hardback book. Recently one day of sales totaled $784.10. That day the bookstore sold 53 paperback books and 45 hardback book. Write a system representing the situation. Use the graph test made the solution of the system. What does the solution mean to the situation? How much does each type of book cost? You substitution to verify your solution.

Answers

The required price of the paperback book and hardback book is $2.95 and $13.95 respectively.

Given that,
The cost of a paperback book is 11 dollars less than the cost of a hardback book. Recently one day of sales totaled $784.10. That day the bookstore sold 53 paperback books and 45 hardback book.

What are simultaneous linear equations?

Simultaneous linear equations are two- or three-variable linear equations that can be solved together to arrive at a common solution.

Here,
Let the price of paperback be x and price of hardback books be y,
According to the question,
x = y - 11 - - - (1)
53x + 45y = 784.10 - - - (2)
From equation 1
53 [y - 11] + 45y = 784.10
y = $13.95

Now,
y = 13.95 - 11
y = $2.95

Thus, the required price of the paperback book and hardback book is $2.95 and $13.95 respectively.

Learn more about simultaneous equations here:

brainly.com/question/16763389

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p = h - 11
53p + 45h = 784.10

just a matter of subbing and solving...
53(h - 11) + 45h = 784.10
53h - 583 + 45h = 784.10
98h = 784.10 + 583
98h = 1367.10
h = 1367.10/98
h = 13.95

p = h - 11
p = 13.95 - 11
p = 2.95

so paperbacks (p) are 2.95 a piece and hardbacks (h) are 13.95 a piece

What is the value of |–46| ?A.
–46







B.
46

Answers

the answer is B that symbol means absolute value and it manes the distance from zero.
The answer is B. The answer is always the positive version of the number.

Rewrite 2/10 : 1/25 as a unit rate.
A. 50:1 B. 1:125 C. 50:10 D. 5:1

Answers

Answer:

D. 5:1

Step-by-step explanation:

Let's break down the fraction \((2)/(10) : (1)/(25)\) into a unit rate.

Firstly, simplify \((2)/(10)\) to \((1)/(5)\). Now, it becomes \((1)/(5) : (1)/(25)\).

To make the denominator of the second fraction match the first one, multiply both the numerator and denominator by 5:

\[ (1)/(5) : (1 * 5)/(25) \]

This simplifies to \((1)/(5) : (5)/(25)\).

Now, both fractions have the same denominator, so we can compare the numerators directly:

\[ 1 : 5 \]

So, the unit rate is 1:5.  D. 5:1

Anits takes 8 hours to build 5 birdhouses. How many birdhouses could she Build in 24 hours?

Answers

The answer would be 15 because the problem states that it takes 8 hours to build 5 birdhouses and they want to know how many she can build in 24 hours if you multiply 8 and 5 with the number 3 you would get 24 hours and 15 birdhouses.

How to solve linear equations by substitution?

5x+2y=9
x+y=-3

Answers

5x+2y=9 x+y=3

change x+y=3 into x=3-y

plug that equation into 5x+2y=9 where x is.

5(3-y)+2y=9

then distribute.

15-5y+2y=9

15-7y=9

minus 15.

-7y=-6

divide both sides by -7.

y is equal to -6/7.

then go back to the first equation and plug in for y.

and then you will get x.

then you will have (y,x)

\begin{cases} 5x+2y=9 \n x+y=-3\end{cases} \n \n\begin{cases} 5x+2*(-3-x)=9 \n y=-3 -x\end{cases} \n \n\begin{cases} 5x-6-2x =9 \n y=-3 -x\end{cases}\n \n\begin{cases} 3x =9+6 \n y=-3 -x\end{cases}

\begin{cases} 3x =15 \ \ /:3 \n y=-3 -x\end{cases} \n \n\begin{cases} x =5 \n y=-3 -5\end{cases} \n \n\begin{cases} x =5 \n y=-8\end{cases}