The required price of the paperback book and hardback book is $2.95 and $13.95 respectively.
Given that,
The cost of a paperback book is 11 dollars less than the cost of a hardback book. Recently one day of sales totaled $784.10. That day the bookstore sold 53 paperback books and 45 hardback book.
Simultaneous linear equations are two- or three-variable linear equations that can be solved together to arrive at a common solution.
Here,
Let the price of paperback be x and price of hardback books be y,
According to the question,
x = y - 11 - - - (1)
53x + 45y = 784.10 - - - (2)
From equation 1
53 [y - 11] + 45y = 784.10
y = $13.95
Now,
y = 13.95 - 11
y = $2.95
Thus, the required price of the paperback book and hardback book is $2.95 and $13.95 respectively.
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–46
B.
46
A. 50:1 B. 1:125 C. 50:10 D. 5:1
Answer:
D. 5:1
Step-by-step explanation:
Let's break down the fraction into a unit rate.
Firstly, simplify . Now, it becomes
.
To make the denominator of the second fraction match the first one, multiply both the numerator and denominator by 5:
This simplifies to .
Now, both fractions have the same denominator, so we can compare the numerators directly:
So, the unit rate is 1:5. D. 5:1
5x+2y=9
x+y=-3
5x+2y=9 x+y=3
change x+y=3 into x=3-y
plug that equation into 5x+2y=9 where x is.
5(3-y)+2y=9
then distribute.
15-5y+2y=9
15-7y=9
minus 15.
-7y=-6
divide both sides by -7.
y is equal to -6/7.
then go back to the first equation and plug in for y.
and then you will get x.
then you will have (y,x)