MATHEMATICS MIDDLE SCHOOL

Show your work and check answer.
4x+1=5x-2

Answers

Answer 1
Answer: Let's solve your equation step-by-step.4x+1=5x−2 Step 1: Subtract 5x from both sides.4x+1−5x=5x−2−5x−x+1=−2 Step 2: Subtract 1 from both sides.−x+1−1=−2−1−x=−3 Step 3: Divide both sides by -1.−x−1=−3−1x=3 Answer:x=3

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3.25, 3.0, 2.75, 2.5, 2.25, ...What is the rule to continue this decimal number pattern?
increase by 0.5
increase by 0.25
decrease by 0.5
decrease by 0.25

Answers

3.25 - 3 = 0.25
3 - 2.75 = 0.25
2.75 - 2.5 = 0.25
2.5 - 2.25 = 0.25

Since we subtracted those numbers, it means we are decreasing.
Therefore, the answer is decrease by 0.25.
you are decreasing by 0.25 . Each time you are subtracting only .25 to each number . +

Use cubes. make doubles. add

Answers

For 1 the answer is 5 + 6 = 11.  So 5 + 6 = 11  For 3: 8 + 7 = 15  For 4: 6 + 5 = 11
4+1+6=12
....................................................
5+6=12

What is the reciprocal of 2 5/7 ?

Answers

2 (5)/(7)...fraction...transform\n (2*7+5)/(7) \n(19)/(7)...invest \n (7)/(19)...this...is... reciprocal

I hope it helps you :)   

it would be 2.57 because with the number you gave us would turn into a decimal

The sides of a square are 3 cm long. One vertex of thesquare is at (2,0) on a square coordinate grid marked in
centimeter units. Which of the following points could
also be a vertex of the square?
F. (−4, 0)
G. ( 0, 1)
H. ( 1,−1)
J. ( 4, 1)
K. ( 5, 0)

Answers

Answer:  The required point that could also be a vertex of the square is K(5, 0).

Step-by-step explanation:  Given that the sides of a square are 3 cm long and one vertex of the  square is at (2,0) on a square coordinate grid marked in  centimeter units.

We are to select the co-ordinates of the point that could also be a vertex of the square.

To be a vertex of the given square, the distance between the point and the vertex at (2, 0) must be 3 cm.

Now, we will be suing the distance formula to calculate the lengths of the segment from the point to the vertex (2, 0).

If the point is F(-4, 0), then the length of the line segment will be

\ell=√((-4-2)^2+(0-0)^2)=√(6^2+0^2)=√(6^2)=6~\textup{cm}\neq 3~\textup{cm}.

If the point is G(0, 1), then the length of the line segment will be

\ell=√((0-2)^2+(1-0)^2)=√(2^2+1^2)=√(4+1)=\sqrt5~\textup{cm}\neq 3~\textup{cm}.

If the point is H(1, -1), then the length of the line segment will be

\ell=√((1-2)^2+(-1-0)^2)=√(1^2+1^2)=√(1+1)=\sqrt2~\textup{cm}\neq 3~\textup{cm}.

If the point is J(4, 1), then the length of the line segment will be

\ell=√((4-2)^2+(1-0)^2)=√(2^2+1^2)=√(4+1)=\sqrt5~\textup{cm}\neq 3~\textup{cm}.

If the point is K(5, 0), then the length of the line segment will be

\ell=√((5-2)^2+(0-0)^2)=√(3^2+0^2)=√(3^2)=3~\textup{cm}.

Thus, the required point that could also be a vertex of the square is K(5, 0).
K (5.0) It's easy just use 2plus3and that's it.

The owner of a dress shop ordered 33 dresses from a new designer. The designer's dresses now make up to 30% of all dresses in the shop. How many dreses are in the shop in all?

Answers

30     33
-----= ----
100     ?
To find this we need to find what makes 30 into 33. 33 divided by 30=1.1
To find ? we need to reverse since it's on the other side. 100 x 1.1=110
110 dresses in total.

Ellie walk 12ft down the hall of his house to get to the door he continues in a straight line out the door and across the yard to the mailbox a distance of 32 ft he came straight back cross the yard 14ft and stopped to pet his dog. how far did you go? please help me

Answers

12 + 32+ 14 feet, equals 58 feet
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