Solve 12ds/w=CD for w.

Answers

Answer 1

Answer: divide 12 on both sides
ds/w=cd/12
now multiply ds on both sides
w=cd/12ds

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How can I solve this square of binomial? (5d - 7d^2t)^2?

Answers

The required simplified value of the square of binomial is 25d² - 70d³t + 49t²d^4 .

Given that,
To solve this square of binomial (5d - 7d²t)².

What is simplification?

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
Using (a - b)² = a² - 2ab + b²
(5d - 7d²t)² = (5d)² - 2 * 5d * 7d²t + (7d²t)²
(5d - 7d²t)² = 25d² - 70d³t + 49t²d^4

Thus, the required simplified value of the square of binomial is 25d² - 70d³t + 49t²d^4 .

Learn more about simplification here: brainly.com/question/12501526

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$(5d - 7d^2t)^2=\n 25d^2-70d^3t+49d^4t^2$

If √6 is the geometric mean between 4 and another number, then the number is

Answers

If you have two numbers x, y. The geometric mean is: √xy

For 4 and x. Geometric Mean = √4x and this is equal to √6

   √4x = √6 Square both sides. The square root disappears.

   4x = 6
   x = 6/4 = 3/2 = 1.5

The other number is 1.5.

If f(x) = 2x + 3 and g(x) = x2 + 1,find f(g(3)).

Answers

Answer:

The value of f(g(3)) is 23.

Step-by-step explanation:

The given functions are

$f(x)=2x+3$

$g(x)=x^2+1$

We have to find the value of f(g(3)).

Substitute x=3 in the function g(x) to find the value of g(3).

$g(3)=3^2+1=9+1=10$

$f(g(3))=f(10)$ [g(3)=10]

Substitute x=10 in the function f(x) to find the value of f(10).

$f(10)=2(10)+3=20+3=23$

Therefore the value of f(g(3)) is 23.

Hello,

f(g(3))=f(3²+1)=f(10)=2*10+3=23
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What is the value of y in the equation 2(4y − 1) = 6?

0
1
6
8

Answers

2(4Y-1)=6
8Y-2=6
8Y=6+2
8Y=8
Y=8/8=1

Answer: y=1

2(4y-1) = 6

simplify

8y-2 = 6

+2 to both sides

8y = 8

/8 to both sides

y=1

Completing the square

x^{2}+3×=0

Answers

${ x }^( 2 )+3x=0\n \n { \left( x+\frac { 3 }{ 2 } \right) }^( 2 )-{ \left( \frac { 3 }{ 2 } \right) }^( 2 )=0\n \n { \left( x+\frac { 3 }{ 2 } \right) }^( 2 )-\frac { 9 }{ 4 } =0$

$\n \n { \left( x+\frac { 3 }{ 2 } \right) }^( 2 )=\frac { 9 }{ 4 } \n \n x+\frac { 3 }{ 2 } =\pm \frac { \sqrt { 9 } }{ \sqrt { 4 } } \n \n x+\frac { 3 }{ 2 } =\pm \frac { 3 }{ 2 } \n \n x=-\frac { 3 }{ 2 } \pm \frac { 3 }{ 2 } \n \n \therefore \quad x=0,\quad and\quad x=-3.$

Serious answers only :) 30 points!

Answers

Okay, using the pythagorean theorem, we can see that the side the both triangles share is... 3.2.

Using the pythagorean theorem again, we do

a^2+b^2=c^2

(3.2)²+a²=6²
10.24+a²=36
a²=25.76

√a²=√25.76
a=5.07543≈ 5.1

Hope this helps!

I believe the answer is 5.1

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