Which is bigger 13% or 3/25?

Answers

Answer 1

Answer: Change 13% as a fraction. It will be 13/100

Now, which is bigger? 13/100 or 3/25
Cross multiply and 13/100 is bigger.

13 3
___ X ____
100 25

13×25=325 and 3×100=300. Now you know 13/100 is bigger.

The answer is 13/100

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Elmer has a collection of 300 fossils. Of these, 21 percent are fossilized snail shells.

Answers

In order to figure out the number of fossilized snail shell, multiply 21% by 300. first change 21% into a decimal, in order to do that, move the percent symbol two spaces to the left, and replace the "%" symbol to a decimal. 0.21 X 300= 63
so 21% of 300 is 63

A snail travels at a rate of 2.35 feet per minute. Write a rule to describe the function. How far will the snail travel in 5 minutes?a. d(t) = 5t; 11.75 ft
b. d(t) = t + 2.35; 7.35 ft
c. d(t) = ; 2.13 ft
d. d(t) = 2.35t; 11.75 ft

Answers

If you would like to know how far will the snail travel in 5 minutes, you can calculate this using the following steps:

2.35 feet per minute
d(t) = 2.35 feet * t minutes = 2.35 * t
t = 5 minutes
d(5) = 2.35 * 5 = 11.75 feet

The correct result would be d. d(t) = 2.35t; 11.75 ft.

Ryan has some nickels and dimes. Altogether, he has 34 coins that total $2.60. Write the system of equations to determine how many of each coin he has.

Answers

34= n+d
2.60=.05n+.1d

To find the amount of dimes that Ryan uses, I used (2.60/0.10) to get 26 dimes, meaning that there are also 8 nickels.

So in total, you have 26 dimes and 8 nickels

Hope this helps

Which of the following is the explicit formulas for the geometric sequence?A. an= 9(1/3)n+1
B. an= 9(3)n-1
C. an= 9(1/3)n-1
D. an= 9(3)n+1

Answers

Answer:

C. an= 9(1/3)n-1

Step-by-step explanation:

The decreasing curve means the base of the exponential factor is less than 1, eliminating choices B and D. The value of the term is 9 at n=1, so eliminating choice A.

The general form of the n-th term is ...

an = a1·r^(n-1) . . . . first term a1, common ratio r

so we expect to see an exponent of (n-1) when a1 is the value for n=1. If you match the pattern above to the answer choices, you see the only decision required is whether r=3 or r=1/3. The decaying curve of the graph shows you that r < 1, so the choice is r=1/3 and the formula is ...

an = 9(1/3)^(n-1) . . . . . . . parentheses are needed on the exponent

Divya wants to rent a car to drive for the weekend. The rental company has a special that allows her to rent it for $200 for the weekend, plus $0.07 per mile. Divya only has $230. Write an inequality, solve, and determine her limitations when renting.

Answers

Answer:

$200 + 0.07m \leq 230$

A maximum of $\approx$ 428 miles is the distance what Divya can travel.

Step-by-step explanation:

Given that:

Rent to be paid for the car in the weekend = $200

Charges to be paid per mile = $0.07

Total money available with Divya = $230

To find:

The inequality as per her limitations and solution to the problem.

Solution:

Let the number of miles for which Divya can drive = $m$ miles

Charges for one mile = $0.07

Charges for $m$ miles = $0.07 $m$

Total charges for renting and $m$ miles = Rental charges + Operational charges

Total charges for renting and $m$ miles = $200 + $0.07 $m$

These are charges must be lesser than equal to the amount of money available with Divya.

Therefore, we can write:

$200 + 0.07m \leq 230$

Subtracting 200 from both the sides:

$0.07m \leq 30$

Dividing both sides with 0.07:

$m \leq (30)/(0.07)\nm\leq 428.6$

Therefore, a maximum of $\approx$ 428 miles is the distance what Divya can travel.

The table below shows data from a survey about the amount of time students spend doing homework each week. The students were either in college or in high school:High Low Q1 Q3 IQR Median Mean σ
College 20 6 8 18 10 14 13.3 5.2
High School 20 3 5.5 16 10.5 11 11 5.4

Which of the choices below best describes how to measure the spread of this data?
A. Both spreads are best described with the IQR.
B. Both spreads are best described with the standard deviation.
C. The college spread is best described by the IQR. The high school spread is best described by the standard deviation.
D. The college spread is best described by the standard deviation. The high school spread is best described by the IQR.

Answers

Answer:

C. The college spread is best described by the IQR. The high school spread is best described by the standard deviation.

Step-by-step explanation:

If data is normally distributed we use Standard deviation otherwise we use Interquartile Range (IQR) for measuring the spread.

Further, data is said to be normally distributed if Mean = Median = Mode.

So, High School data is normally distributed but College data is not.

So, We measure the spread of College data by IQR and High School data by Standard Deviation.

Thus, Option C is the only correct option.

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