Is 2/6 greater than 2/8

Answers

Answer 1
Answer: yes 2/6 is greater than 2/8 because when simplified 2/6 is 1/3 and 2/8 is 1/4 1/3 is larger than 1/4 because 1/4 is equal to 25% while 1/3 is equal to 33% hope that helped
Answer 2
Answer: Yes it is. 
2/6= 1/3
2/8= 1/4
1/3 is greater than 1/4.

Related Questions

In 1 hour how many more times does a rabbits heart beat than a dogs rabbits heart beat per 1 minute 212 dogs heart beat per 1 minute
Divide 7/8 divided by 1/4 A) 3 1 2 Eliminate B) 4 C) 7 16 D) 7 32 please help quickly
Solve the equation 5w = 20
I need help:Sarah has red, green and blue t-shirts. 2/3 of all t shirts are red1/3 of all t shirts are greenWhat fraction of all t shirts are blue?
Wes has a piece of land with side lengths of 36.2 m, 41.6 m, 39.4 m, and 31.2 m. He also has 150 m of tape to mark the boundaries of the land. After Wes marks the land, how much tape will he have left over?

Please solve this, asap.

Answers

2^(1/12) because math math math math math 
0.1317582337

Used a calculator.

Simplify six-hundred thirty over 10

Answers

630/10 

Lets divide!

630/10 = 63
10/10 = 1

63/1 = 63

Answer: 63
The answer is 63 because six-hundred thirty = 630  and 630 over 10 means to divide which will equal 630/10=63 and that's the answer 63

Mr. Stevens bought 8 liters of soda for a party. His friends drank 1 liter. What fraction of the soda did his guests drink? What fraction of the soda was left?

Answers

1/8 is the fraction of the people who drank the soda, and 7/8 is the fraction of the soda that is left

7.2 cw homework help

Answers

Answer:

31. Yes (Y)

WXYZ ~ DABC

S.F.=4


32. Yes (Y)

GHIJ ~ KLMN

S.F.=2/3


33. Missing length: 16


34. Missing length: 30


35. x=7


36. x=10


Step-by-step explanation:

31. The polygons are similar if:

WX/DA=XY/AB

Then:

WX/DA=24/6→WX/DA=4

XY/AB=16/4→XY/AB=4

Like WX/DA=4=XY/AB, the polygons WXYZ and DABC are similar

Scale Factor: S.F.=XY/DA=XY/AB→S.F.=4


32. The polygons are similar if:

GH/KL=HI/LM=IJ/MN=GJ/KN

Then:

GH/KL=6/9=(6/3)/(9/3)→GH/KL=2/3

HI/LM=4/6=(4/2)/(6/2)→HI/LM=2/3

IJ/MN=4/6=(4/2)/(6/2)→IJ/MN=2/3

GJ/KN=4/6=(4/2)/(6/2)→GJ/KN=2/3

Like GH/KL=HI/LM=IJ/MN=GJ/KN=4, the polygons GHIJ and KLMN are similar

Scale Factor: S.F.=GH/KL=HI/LM=IJ/MN=GJ/KN→S.F.=2/3


33. If the polygons are similar, their sides must be proportional, then:

x/24=10/15

Simplifying the fraction on the right sides of the equation, dividing the numerator ans denominator by 5:

x/24=(10/5)/(15/5)

Dividing:

x/24=2/3

Solving for x: Multiplying both sides of the equation by 24:

24(x/24)=24(2/3)

Multiplying:

x=8(2)

x=16


34. If the polygons are similar, their sides must be proportional, then:

54/63=(54/9)/(63/9)→54/63=6/7

48/56=(48/8)/(56/8)→48/56=6/7

x/35=6/7

Solving for x: Multiplying both sides of the equation by 35:

35(x/35)=35(6/7)

Multiplying:

x=5(6)

x=30


36. (8x-2)/63=42/49

Simplifying the fraction on the right sides of the equation, dividing the numerator ans denominator by 7:

(8x-2)/63=(42/7)/(49/7)

Dividing:

(8x-2)/63=6/7

Solving for x: Multiplying both sides of the equation by 63:

63(8x-2)63=63(6/7)

Multiplying:

8x-2=9(6)

8x-2=54

Adding 2 both sides of the equation:

8x-2+2=54+2

Adding:

8x=56

Dividing both sides of the equation by 8:

8x/8=56/8

Dividing:

x=7


37. (6x-6)/63=42/49=30/35

Simplifying the fractions

(6x-6)/63=(42/7)/(49/7)=(30/5)/(35/5)

Dividing:

(6x-6)/63=6/7

Solving for x: Multiplying both sides of the equation by 63:

63(6x-6)63=63(6/7)

Multiplying:

6x-6=9(6)

6x-6=54

Adding 6 both sides of the equation:

6x-6+6=54+6

Adding:

6x=60

Dividing both sides of the equation by 6:

6x/6=60/6

Dividing:

x=10



What is the lateral area of a rectangular prism with a base length of 16 m, a base width of 8 m, and a height of 4 m? A.
48 m2

B.
192 m2

C.
52 m2

D.
512 m2

Answers

Answer:  B. 192\ m^2

Step-by-step explanation:

The lateral area of a rectangular prism is given by :-

\text{Lateral Area}=2h(l+w), where h is the height, l is the length and w is the width of the rectangular prism.

Now, using the given information, the lateral area of the rectangular prism will be :-

\text{Lateral Area}=2(4)(16+8)=8(24)=192\ m^2

B. because you do 16*2*h + 8*2*h and you get 128 + 64 = 192

Tomas drew a rectangle with an area of 6 cm² what is the greatest possible perimeter for this rectangle

Answers

The greatest perimeter would be 12 cm