Salinity refers to what?A. density
B. pressure
C. temperature
D. dissolved salt
Answers
Answer:
The answer is D. dissolved salt hopefully this helps!
Final answer:
Salinity refers to the amount of dissolved salt in a body of water. It affects the types of organisms that can live in that water due to the effects of salinity on cellular hydration. Certain organisms are adapted to survive differing levels of salinity.
Explanation:
Salinity refers to the amount of dissolved salt in a body of water. It is usually expressed as the number of grams of salt per kilogram of water. The salinity of a body of water can have significant impacts on its ecosystem, including the types of organisms that can survive there.
For instance, high salinity levels can cause cells to dehydrate, making it difficult for some organisms to survive. On the other hand, certain organisms like halophiles thrive in high salinity conditions. Therefore, understanding salinity is crucial in studying marine and aquatic biology.
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Related Questions
1. Science is different than many other ways of thinking because it is based on-opinions-facts-personal viewpoints-none of the above
MATCH THE FOLLOWING!!!(match each instrument with its description)1. weather maps/satellite 2. Doppler radar 3. radiosonde 4. wind vane 5. psychrometer __________________________________________________________________________A. uses two thermometers; a dry and wet bulb B. points in the direction winds are coming from C. uses frequency waves to track particle movement D. used to help track air masses and fronts E. carried with a weather balloon
Which substance is a binary acid
3. Sulfur dioxide (SO2) can be reduced by hydrogen disulfide (H2S), producing sulfur in its elemental form and water (H2O). Using Hess’s law and the reactions below, determine the overall enthalpy for the reaction between SO2 and H2S. Make to clearly show your work.H2 (g) + S (s) → H2S (g) ΔH = –20.6 kJ SO2 (g) → S (s) + O2 (g) ΔH = +296.8 kJ 2H2 (g) + O2 (g) → 2H2O (g) ΔH = –285.8 kJ
12 SSO
Answers
Answer:
7.5 moles of hydrogen is required
Explanation:
Given data:
Number of moles of H₂ needed = ?
Number of moles of NH₃ = 5 mol
Solution:
Chemical equation:
N₂ + 3H₂ → 2NH₃
Now we will compare the moles of ammonia and hydrogen.
NH₃ : H₂
2 : 3
5 : 3/2×5 = 7.5 mol
Thus, 7.5 moles of hydrogen is required.
Answers
Final answer:
The question is asking about the mathematical relationship between mass, volume and density in Physics, which is represented by the formula D = m/V; this formula is essential in various physics computations.
Explanation:
The relationship between the mass (m) of a material, its volume (V), and its density (D) is represented by the formula D = m/V. This is a fundamental concept in Physics, specifically in areas involving fluid mechanics and material science. If you know the mass and volume of a material, you calculate its density using this formula, and decipher a lot about the material's properties from the result of this calculation.
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Answers
Answers
Answer:
The net charge of 1.3 g nugget of pure gold after 1.68% of its electrons are removed is 559 C
Explanation:
When an atom gains electrons it becomes negatively charged. Conversely, when it looses electrons the atoms becomes positively charged thus
To solve this question, we rely on the relationship between the nmber of particles present in a given mass of an atom, Avogadro's number and number of moles, n
The given variables are
mass of pure gold nugget = 1.30 g
Quantity of electrons removed = 1.68% of electrons present in the gold sample
Molar mass of gold = 197 g/mol
Avogadro's number = 6.02 × 10²³ atoms/mole
qc = one electron charge = -1.06 × 10⁻¹⁹ C/electron
Electrical charge of gold nugget = 0 C
Number of electrons in one gold atom = 79 electrons
Solving for the number of prticles or gold atoms in 1.3 grams of gold we get
n mass/(molar mass) = 1.3/197 moles of gold = 0.0066 moles
number of particles in 0.0066 moles of gold N = n× = 0.0066 × 6.02 × 10²³ = 3.97 × 10²¹ atoms
since 79 electrons are present per particle we have
3.97 × 10²¹ × 79 = 3.14 × 10²³ electrons
quantity of elecrtrons removed = 1.68% of 3.14 × 10²³ electrons =1.68/100 × 3.14 × 10²³ electrons = 0.0168 × 3.14 × 10²³ electrons = 5.3 × 10²¹ electrons
The net charge of 5.3 × 10²¹ electrons = 5.3 × 10²¹ electrons × -1.06 × 10⁻¹⁹ C/electron =
5.59 × 10² C = 559 C
how is the amount of neutrons determined?
Answers
The ionic charge is the number of protons subtracted by the number of electrons. They usually have the same charge, but with opposite signs, Electrons ( -) and protons ( +)
To find the neutron number,subtract the proton number from the atomic mass. It will give you the neutron number.
Hope this helps.
Answers
Begin by balancing the equation:
2 Fe2O3 —> 4 Fe + 3 O2
Start your stoic:
(79.2g Fe2O3) <—- you start with what you have and always try to get rid of what unit you are at
Conversion to get rid of grams is
# grams over mole
^
This number comes from periodic table
Add whole mass of Fe2O3= 159.697g
(79.2g Fe2O3)(. mole. )
(159.697g)
Now get rid of moles, this is where you used the balanced numbers at the beginning
The number you are looking for goes on top—> (4 moles Fe)
(2 moles Fe2O3)
Last get mass of Fe alone and plug in to calc
Whole equation:
(79.2g)( moles)(4mFe)(55.85gFe)
(159.697)(2mole)(mole)
79.2 divides by 159.697 multiplied by 4 divided by 2 multipled by 55.85 equals 55.396406 rounded to:
55.4 g Fe
Answer: The mass of iron present is 55.40 g
Explanation:
We know that:
Molar mass of iron (III) oxide = 159.7 g/mol
Molar mass of iron = 55.85 g/mol
We are given:
Mass of iron (III) oxide = 79.2 g
To calculate the mass of iron in given amount of iron (III) oxide, we use unitary method:
In 159.7 grams of iron (III) oxide, the mass of iron is (2 × 55.85) = 111.7 g
So, in 79.2 grams of iron (III) oxide, the mass of iron will be =
Hence, the mass of iron present is 55.40 g