If 28% of a sum is $100.80, what is the sum? A. $282.24 B. $129.02 C. $277.78 D. $360.00

Answers

Answer 1

Answer: Its D. $360.00 i hope its right

Answer 2

Answer: 100/28*100.80=(360.00) D hope this helps

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Use the coordinate plane, the figure below, coordinate proof strategies, and the lengths and slopes of PM and GR to verify this theorem: Given: QUAD is a quadrilateral. P, G, R, M are the midpoints of the sides QU, UA, AD, and DQ respectively. Prove: The polygon formed by joining adjacent midpoints of a quadrilateral is a parallelogram.

Answers

The "respectively" part is removed so what is the question

Calculate how much each size per gram, and circle which gives the best value for money. 250g for $2.30, 400g for &3.40, 1Kg for $5.65

Answers

To do this, we must set up ratios:
Option One:
$(2.30)/(250g) \n (0.0092)/(1g) \n 0.0092/g$
The first options costs only $0.0092/gram (a fraction of a penny)!
Option Two:
$(3.40)/(400g) \n (0.0085)/(1g) \n 0.0085/g$
The second option costs only $0.0085/gram (cheaper than option one)!
Option Three:
This requires a little more work. First, we have to convert the grams into kilograms. For every 1 kg, there is 1,000 g. Therefore, 1,000g costs $5.65. Next, we set up the ratio as usual:
$(5.65)/(1000g) \n (0.00565)/(1g) \n 0.00565/g$
The third option costs $0.00565/gram.

Therefore, option three is the cheapest!

Hope this helps!

If 6y-8=28, what is the value of y

Answers

The answer would be y = 6

6y-8=28
add 8 to both sides
6y=36
divide both sides by 6
y=6

If sqrt x=-7 then x=-49
true or false

Answers

False.

IF √x = -7.

Square both sides

(√x)² = (-7)²

x = (-7)(-7)

x = 49

x will equal 49

False is your answer

hope this helps

4=(-8)+3x solve for x

Answers

Answer: x=4
4=-8+3x
4+8=+8+3x
12=3x
x=4

4=(-8)+3x -3x=-8-4 -3x=-12 X=-12 divided by -3 X=4

Refer to the figure and find the volume V generated by rotating the given region about the specified line.R3 about AB

Answers

Answer:

Hence, volume is: $(34\pi)/(45)$ cubic units.

Step-by-step explanation:

We will first express our our equation of the curve and the line bounded by the region in terms of the variable y.

i.e. the curve is re $x=(1)/(16)y^4$

and the line is given as: $x=(1)/(2)y$

Since after rotating the given region $R_(3)$ about the line AB.

we see that for the following graph

the axis is located at x=1.

and the outer radius(R) is: $(1)/(16)y^4$

and the inner radius(r) is: $(1)/(2)y$

Now, the area of the graph= area of the disc.

Area of graph= $\pi(R^2-r^2)$

Now the volume is given as:

$Volume=\int\limits^2_0 {Area} \, dy$

On calculating we get:

Volume= $(34\pi)/(45)$ cubic units.

The volume V generated by rotating the given region about the specified line R3 about AB is $\boxed{\frac{{34\pi }}{{45}}{\text{ uni}}{{\text{t}}^3}}.$

Further explanation:

Given:

The coordinates of point A is $\left( {1,0} \right).$

The coordinates of point B is $\left( {1,2} \right).$

The coordinate of point C is $\left( {0,2} \right).$

The value of y is $y = 2\sqrt[4]{x}.$

Explanation:

The equation of the curve is $y = 2\sqrt[4]{x}.$

Solve the above equation to obtain the value of x in terms of y.

$\begin{aligned}{\left( y \right)^4}&={\left( {2\sqrt[4]{x}} \right)^4} \n{y^4}&=16x\n\frac{1}{{16}}{y^4}&= x\n\end{aligned}$

The equation of the line is $x = (1)/(2)y.$

After rotating the region ${R_3}$ is about the line AB.

From the graph the inner radius is ${{r_2} = (1)/(2)y$ and the outer radius is ${{r_1}=\frac{1}{{16}}{y^4}.$

${\text{Area of graph}}=\pi\left( {{r_1}^2 - {r_2}^2} \right)$

$Area = \pi\left( {{{\left({\frac{1}{{16}}{y^4}} \right)}^2} - {{\left({(1)/(2)y} \right)}^2}}\right)$

The volume can be obtained as follows,

$\begin{aligned}{\text{Volume}}&=\int\limits_0^2 {Area{\text{ }}dy}\n&=\int\limits_0^2{\pi \left( {{{\left({\frac{1}{{16}}{y^4}} \right)}^2} - {{\left( {(1)/(2)y} \right)}^2}} \right){\text{ }}dy}\n&= \pi \int\limits_0^2 {\left( {\frac{1}{{256}}{y^8} - (1)/(4){y^2}} \right){\text{ }}dy}\n\end{aligned}$

Further solve the above equation.

$\begin{aligned}{\text{Volume}}&=\pi \left[ {\int\limits_0^2 {\frac{1}{{256}}{y^8}dy - } \int\limits_0^2{(1)/(4){y^2}{\text{ }}dy} } \right]\n&= \frac{{34\pi }}{{45}}\n\end{aligned}$

The volume V generated by rotating the given region about the specified line R3 about AB is $\boxed{\frac{{34\pi }}{{45}}{\text{ uni}}{{\text{t}}^3}}.$

Learn more:

1. Learn more about inverse of the functionbrainly.com/question/1632445.

2. Learn more about equation of circle brainly.com/question/1506955.

3. Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Volume of the curves

Keywords: area, volume of the region, rotating, generated, specified line, R3, AB, rotating region.

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