To represent 63 as a sum of tens and ones, divide 63 into multiples of ten (tens) and the remainder (ones). It will be 6 tens and 3 ones.
The number 63 can be written as a sum of tens and ones. You can do this by dividing the number into tens or multiples of ten and the remaining will be ones.
In case of 63, the largest multiple of ten that is less than 63 is 60 (which is 6 tens) and the remaining number is 3 (which is 3 ones).
Therefore, 63 can be written as the sum of 60 (6 tens) + 3 (3 ones).
So the answer is 6 tens + 3 ones.
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Answer:
3/8 mile in 3/5 hour
Step-by-step explanation:
I am taking the test right now
Answer:
The total cost to print n calendars is the sum of the cost of printing each calendar and the one-time cost for taking the photos:
Total cost = (Cost per calendar * Number of calendars) + One-time cost for photos
Given that the cost per calendar is $5.50 and the one-time cost for photos is $200, the equation can be written as:
Total cost = 5.50n + 200
Now, we know that the club has $1500 to cover the initial costs of the calendars. Therefore, the equation can be set equal to $1500:
5.50n + 200 = 1500
So, the equation representing the number of calendars the club can print is 5.50n + 200 = 1500, where n is the number of calendars.
Step-by-step explanation:
2x-5y=1
What is the solution?