MATHEMATICS MIDDLE SCHOOL

What is the hardest part/ subject in math?

Answers

Answer 1
Answer: In my opinion, everything can seem hard, but as long as you practice, you'll get the hang of it. 

The hardest part may have to be sigma notation, which includes a-lot of formulas and calculus. 
Answer 2
Answer: Fractions is the hardest for me.

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Five less than 3 times the length, l

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The equation would be 3l-5.

A catering service offers 9 appetizers 8 main courses and 3 desserts. A customer is to select 6 appetizers 5 main courses and 2 desserts for a banquet. In how many ways can this be done?

Answers

Answer:   14112

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Explanation:

We'll be using the n C r combination function. To make the notation a bit easier to deal with, I will write "C(n,r)" instead of "n C r".

The formula is

C(n,r) = (n!)/(r!*(n-r)!)

where the exclamation marks represent factorials.

A factorial is where you start with a positive integer, and count down to 1 multiplying all along the way.

Examples:

5! =           5*4*3*2*1

8! = 8*7*6*5*4*3*2*1 = 120

Note how the string "5*4*3*2*1" is in both 5! and 8!

We can say 8! = 8*7*6*5!

Because we can replace the "5!" at the end with "5*4*3*2*1" later if we wanted. This strategy is used to help find a shortcut to simplification.

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We have n = 9 appetizers and r = 6 items we can select from this pool.

C(n,r) = (n!)/(r!*(n-r)!)

C(9,6) = (9!)/(6!*(9-6)!)

C(9,6) = (9!)/(6!*3!)

C(9,6) = (9*8*7*6!)/(6!*3*2*1)

C(9,6) = (9*8*7)/(3*2*1) .... the "6!" terms canceled out

C(9,6) = 504/6

C(9,6) = 84

There are 84 ways to choose six appetizers from the pool of nine available

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Repeat those steps for the main courses. Use n = 8 and r = 5 this time.

C(n,r) = (n!)/(r!(n-r)!)

C(8,5) = (8!)/(5!*(8-5)!)

C(8,5) = (8!)/(5!*3!)

C(8,5) = (8*7*6*5!)/(5!*3*2*1)

C(8,5) = (8*7*6)/(3*2*1)

C(8,5) = (336)/(6)

C(8,5) = 56

There are 56 ways to choose five main course meals from the pool of eight available

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Then do the same for the desserts. Use n = 3 and r = 2.

C(n,r) = (n!)/(r!(n-r)!)

C(3,2) = (3!)/(2!*(3-2)!)

C(3,2) = (3!)/(2!*1!)

C(3,2) = (3*2*1)/(2*1*1)

C(3,2) = 6/3

C(3,2) = 3

There are 3 ways to choose two desserts from the pool of three available

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The last step is to multiply all these results:

84*56*3 = 14112

This is the number of ways to select all of the items given the restrictions listed. The order does not matter.

I need help on 1/2/3/4

Answers


You may need to sit down with your parents or with your teacher and
go over how to add and subtract fractions.

1).  "Perimeter" means the distance all the way around the square.
With a square, all 4 sides are the same length.  With this square,
every side is 1-1/4 inches long.

Perimeter = length of all 4 sides= (1-1/4) + (1-1/4) + (1-1/4) + (1-1/4) =

                                               (1 + 1 + 1 + 1) + (1/4 + 1/4 + 1/4 + 1/4) =

                                                         4           +             4/4  =  5 inches .

2).  (2-3/8) + (1-7/8) = (2 + 1) + (3/8 + 7/8) =

                                        (3)   +    (10/8) =

                                         3    +      1-1/4 =        4-1/4 .

3).  The difference is  (1-1/6) minus (5/6) .

Before you start to do the subtraction, write the (1-1/6)  as  (7/6) .

Then the subtraction is    (7/6) - (5/6)  =  2/6  =  1/3 .

4).  This one is almost the same kind of problem as #3. 
It's another subtraction.

If you need (2-1/4) all together, and you already have (1-3/8),
then the amount you still have to find, or borrow, or buy, is the
difference between those two numbers.

           (2-1/4) minus (1-3/8) .

The trick is to write the (2-1/4) in some form that you'll be able to
subtract (1-3/8) from it.  When I learned how to do that, it was called
'borrowing', but I think now it's called 'regrouping'.

We need to work on (2-1/4):

-- take 1 from the 2, and change it into fourths.
 
                 2-1/4  =  1 and 4/4 and 1/4  =  1 and 5/4

-- Now, take those 5/4, and turn them into eighths.                
   Each fourth makes 2 eighths.  So  5/4  =  10/8.

Now, the (2-1/4) has turned into  1-10/8 .
We did NOT change the value.  It's still the same amount
as 2-1/4 , but it's just written in a different way.
And now the subtraction is easy:

         (2-1/4) minus (1-3/8)  = 

       (1-10/8) minus (1-3/8)  =  (zero and 7/8).

You need  7/8 inch  more string than you already have.

         

What is the measure of xyz

Answers

Do you have a picture or the graphed numbers? I’d like to help

Describe how you can use a 30 cm ruler to measure ribbon for each length

Answers

Just put each end and that's it

Tiffany pays 40$ for 160 minutes of talk time on her cell phone.How many minutes of talk time does she get per dollar?

Answers

To find how many minutes of talk time is available per dolla, you have to divide 160 (number of minutes) by 40 (cost)160/40 = 4Therefore, it's 4 minutes per dollar
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