What is m ∠ 11?
Step-by-step explanation:
Let the first term = a and common difference = d
Given,
= 729 and = 243
To find, the first term of the given sequence (a) = ?
We know that,
The nth term of a G.P.
The 3rd term of a G.P.
⇒ = 729 ..............(1)
The 4th term of a G.P.
⇒ = 243 ..............(2)
Dividing equation (2) by (1), we get
=
⇒
Put in equation (1), we get
= 729
⇒ = 729
⇒ a = 9 × 729 = 6561
∴ The first term of the given sequence (a) = 6561
The first term of the geometric sequence is 6561 and the recursive rule of the sequence is a(n) = a(n-1) * 1/3.
In a
geometric sequence
, each term after the first is found by multiplying the previous term by a fixed, non-zero number called the
common ratio
. In your case, you are given the third term, a3=729, and the fourth term, a4=243 in the sequence. We know that in a geometric sequence, any term divided by the previous term gives the common ratio. So 243/729 = 1/3, which is the common ratio, r.
Now, to find the first term, we use the provided values and the formula for the nth term in a geometric sequence which is a = a3 / r^n, where a is the first term, r is the common ratio, and n is the term number. Therefore, to find the first term, we go back two steps from the third term (729) dividing by 1/3 each time: (729/1/3) = 2187 (which is the second term) and again (2187/1/3) = 6561 (which is the first term).
So, the first term, a1=6561, and the recursive rule that describes this sequence is a(n) = a(n-1) * 1/3
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