Derivative of R=(100+50/lnx)

Answers

Answer 1
Answer:

Answer:

\displaystyle R' = (-50)/(x(\ln x)^2)

General Formulas and Concepts:

Calculus

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle (d)/(dx) [cf(x)] = c \cdot f'(x)

Derivative Property [Addition/Subtraction]:                                                         \displaystyle (d)/(dx)[f(x) + g(x)] = (d)/(dx)[f(x)] + (d)/(dx)[g(x)]

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹  

Derivative Rule [Quotient Rule]:                                                                           \displaystyle (d)/(dx) [(f(x))/(g(x)) ]=(g(x)f'(x)-g'(x)f(x))/(g^2(x))

Step-by-step explanation:

Step 1: Define

Identify

\displaystyle R = 100 + (50)/(\ln x)

Step 2: Differentiate

  1. Derivative Property [Addition/Subtraction]:                                                 \displaystyle R' = (d)/(dx)[100] + (d)/(dx) \bigg[ (50)/(\ln x) \bigg]
  2. Rewrite [Derivative Property - Multiplied Constant]:                                   \displaystyle R' = (d)/(dx)[100] + 50 (d)/(dx) \bigg[ (1)/(\ln x) \bigg]
  3. Basic Power Rule:                                                                                         \displaystyle R' = 50 (d)/(dx) \bigg[ (1)/(\ln x) \bigg]
  4. Derivative Rule [Quotient Rule]:                                                                   \displaystyle R' = 50 \bigg(((1)' \ln x - (\ln x)')/((\ln x)^2) \bigg)
  5. Basic Power Rule:                                                                                         \displaystyle R' = 50 \bigg( (-(\ln x)')/((\ln x)^2) \bigg)
  6. Logarithmic Differentiation:                                                                         \displaystyle R' = 50 \bigg( ((-1)/(x))/((\ln x)^2) \bigg)
  7. Simplify:                                                                                                         \displaystyle R' = (-50)/(x(\ln x)^2)

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation


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Write the equation in standard form. 0.5x = y - 4

Answers

Answer:

y=0.5x+4

Step-by-step explanation:

0.5x= y-4

add 4 on both sides

and then you get:

y=0.5x+4

Answer:

y = 0.5x + 4, or y = 1/2x + 4 (if you prefer fractions)

Step-by-step explanation:

y = mx + b (slope intercept form / standard form) ; m = 0.5 or 1/2, b = 4.

m = linear coefficient/slope(denoted by a in a 1 degree binomial)

b = constant coefficient / y-intercept (denoted by b in a 1 degree binomial)

to convert this equation into a standard form equation. You need to isolate y and leave the coefficients on the other side.

0.5x = y - 4

0.5x (+4) = y - 4 (+4)

0.5x + 4 = y

y = 0.5x + 4

What 3 numbers multiply to get 63?

Answers

The three numbers to multiply to get 63 is A = 3 x 3 x 7

Given data ,

Let the number be represented as A

where the value of A = 63

Let the three numbers be represented as a , b , c

where the a , b , c are the factors of A

The factorization of the number 63 will be the three numbers to multiply to get the number 63

So , prime factorization of 63 is: 3 x 3 x 7

Hence , the three numbers are 3 , 3 and 7

To learn more about factorization click :

brainly.com/question/804076

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There are many combinations if the numbers are not required to be integers.

If they are required to be integers, I'd suggest:

3*7*3 = 63

How to cut 22 inches x 28 inches into 8 1/2 x 11
PLEASE HELP ME 20 POINTS!!!!!

Answers