Karyn proofreads 15 pages in 2 for $40 how much does she revive on average for a page

Answers

Answer 1
Answer: As far as i can understand the question, it is given that Karen proofreads 15 pages. She gets a rate of $40 for proofreading 2 pages. The money Karen makes for proofreading 15 pages has to be determined.
Number of pages Karen proofreads = 15
Then
For proofreading 2 pages Karen receives = 40 dollars
So
For proofreading 15 pages, Karen receives = (40/2) * 15 dollars
                                                                       = 20 * 15 dollars
                                                                       = 300 dollars
So Karen receives $300 for proofreading 15 pages. I hope this is what you were looking for and the procedure for solving the problem is also clear to you.

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Simplify 10 to the power of 0

Answers

any number to the power of 0 equals 1

hope this helps :)

Answer:

i think it is 0

Step-by-step explanation:

LAST QUESTION TODAY!! 1/3 of 18 is....? Thanks so much

Answers

Answer:

6

Step-by-step explanation:

1/3 x 18 = 6

6

18 x 1/3 = 18/3, which is 6

Write the sum of numbers as a product in their GPS and another sum 44+40

Answers

GCF(44,40)=4\n\n44+40=4(11+10)

Compare and contrast tax and discount.

Answers

Tax is adding to what your pay is and discount is reducing the price of the thing your buying.That is what is diffrent about it.One is adding and one is subtracting.I don't know whats the same, this is just contrasting.

Solve for y:-

y + 8 = 35

Thank you!

Answers

To solve for y we need to use the inverse operation of addition which is subtraction. Lets do it:-

y + 8 = 35
y = ?
35 - 8 = ?
35 - 8 = 27
y = 27

CHECK OUR WORK:-
 
y + 8 = 35
y = 27
27 + 8 = ?
27 + 8 = 35
We were RIGHT!!!!

So, y = 27.

Hope I helped ya!! xD
y + 8 = 35
    
Subtract 8 from both sides because its the inverse operation. 

y + 8 = 35
y = 35 - 8
y = 27

Answer: y = 27

34 packages are randomly selected from packages received by a parcel service. The sample has a mean weight of 25.9 pounds and a standard deviation of 3.8 pounds. What is the 95% confidence interval for the true mean weight, μ, of all packages received by the parcel service?24.6 < μ < 27.2

24.8 < μ < 27.0

24.2 < μ < 27.6

24.4 < μ < 27.4

Answers

The 95% confidence interval for the true mean weight, μ, of all packages received by the parcel service is;

Option A; 24.6 < μ < 27.2

We are given;

Sample mean; x' = 25.9 pounds

Standard deviation; σ = 3.8 pounds

Confidence level; CL = 95%

Sample size; n = 34

Now formula for confidence interval is;

CI = x' ± z( σ/√n)

Where z is critical value at given confidence level.

z at CL of 95% is; z = 1.96

Thus;

CI = 25.9 ± 1.96(3.8/√34)

CI = 25.9 ± 1.3

CI = (25.9 - 1.3), (25.9 + 1.3)

CI = (24.6, 27.2)

Read more at; brainly.com/question/12970960

Answer:

24.6 < μ < 27.2

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = (1-0.95)/(2) = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*(\sigma)/(√(n))

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96(3.8)/(√(34)) = 1.3

The lower end of the interval is the sample mean subtracted by M. So it is 25.9 - 1.3 = 24.6 pounds.

The upper end of the interval is the sample mean added to M. So it is 25.9 + 1.3 = 27.2 pounds.

So the correct answer is:

24.6 < μ < 27.2