The race begins at a rate of 1.5 meters per second. what distance, d, is covered after, t, seconds

Answers

Answer 1

Answer:

The required distance after time t is given as 1.5t.

Given that,
Speed in the race is given as 1.5 meters per second, to determine distance, d, is covered after, t, seconds.

What is Distance?

Distance is defined as the object traveling at a particular speed in time from one point to another.

What is speed?

Speed is defined as when an object is subjected to movement, the distance covered by the object in a certain time interval is the speed of that object.

Here,
Speed = 1.5 m/s
Distance = speed × time
Distance = 1.5 × t
Distance(d) = 1.5t

Thus, the required distance after time t is given as 1.5t.

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Answer 2

Answer: Well if 1.5 m is covered in 1 second, the distance would be calculated as d=1.5t.

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a 5ft ladder is leaning against a 4 ft wall. how far must the bottom of the ladder be from the wall so that the top of the ladder rests on the top of the wall?

Answers

The ladder leaning against the wall forms a right angled triangle with the gound and the wall. So we can use the formula:

a² + b² = c²

The ladder is the hypotenuse c²

The vertical leg is b²

The base or horizontal leg is a²

We need to find the length of the base a², so:

a² = c² - b²

a² = 5² - 4²

a² = 25 - 16

a² = 9

a = √9

a = 3

Therefore the bottom of the ladder must be 3 feet from the wall.

How to find the inverse of the function f(x)=2x-3 ? Please

Answers

$f(x)=2x-3\n\ny=2x-3\n\n-2x=-y-3\ \ \ \ /:(-2)\n\nx=(1)/(2)y+(3)/(2)\n\nf^(-1)(x)=(1)/(2)x+(3)/(2)$

f(x)=2x-3
y=2x-3
x=(y+3)/2

f⁻¹(x) = (x+3) / 2

John needs to make a scale drawing of his school building for art class. If the building is 256.25 meters long, and John scales it down using a ratio of 25 meters to 1 inch, how long will the building be in the sketch?

Answers

So we want to know how long will the scale drowing of the building be if the building is 265.25m long and the scale is 1 inch on the drawing is equal to 25 meters of the building. To find the answer lets scale the building. If the real length of the building is 256.25 meters, then the number of inches will be: 256.25/25=10.25 inches.

Divide. (3a3 + 6a2) ÷ 3a how do I do this?

Answers

$( 3a^3 + 6a^2 )/(3a)=(3a ( a^2 + 2a ) )/(3a)= a^2 + 2a =a(a+2)$

Dx+hy=j what does x=

Answers

$dx+hy=j\n\ndx=j-hy\ /:d\ \ \ \ and\ \ \ \ d \neq 0\n\nx= (j-hy)/(d)$

$dx+hy=j\n \n dx=j-hy\n \n \boxed{x=(j-hy)/(d)}$

A welder needs apiece of half-inch pipe18 3/4 in. Long. she has a piece the is 28 1/8 in. Long. how much must she cut off from the longer piece?

Answers

I got 9 and 3/8 because you would subtract 18 3/4 from 28 1/8

Final answer:

The welder needs to cut off 9 3/8 inches from the longer piece.

Explanation:

To determine how much the welder needs to cut off from the longer piece of pipe, we need to find the difference between the lengths of the two pieces.

Given that the longer piece is 28 1/8 inches and the desired length is 18 3/4 inches, we can subtract the desired length from the longer piece's length:

28 1/8 - 18 3/4 = 9 3/8

Therefore, the welder needs to cut off 9 3/8 inches from the longer piece of pipe.

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