Paul is three times as old as Mary and Peter is four times as old as Mary,If the sum of their ages is 64, how old are Peter,Paul,and Mary.
Answers
Answer 1
Answer:
Let Mary's age be x.
Paul is three times as old as Mary, so Paul's age would be 3x.
Peter is four times as old as Mary, so Peter's age would be 4x.
The sum of their ages is 64
⇒ Paul's age+ Peter's age+ Mary's age= 64
⇒ 3x+ 4x+ x= 64
⇒ 8x= 64
⇒ x= 64/8
⇒ x= 8
Paul's age is: 3x= 3*8= 24
Peter's age is: 4x= 4*8= 32
Final answer: Paul is 24 years old.
Peter is 32 years old.
Mary is 8 years old.
Hope this helps~
Paul is three times as old as Mary, so Paul's age would be 3x.
Peter is four times as old as Mary, so Peter's age would be 4x.
The sum of their ages is 64
⇒ Paul's age+ Peter's age+ Mary's age= 64
⇒ 3x+ 4x+ x= 64
⇒ 8x= 64
⇒ x= 64/8
⇒ x= 8
Paul's age is: 3x= 3*8= 24
Peter's age is: 4x= 4*8= 32
Final answer: Paul is 24 years old.
Peter is 32 years old.
Mary is 8 years old.
Hope this helps~
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TheProfessor35's answer is correct, but here's a step by step as you asked. PEMDAS stands from Parentheses Exponents Multiplication Division Addition Subtraction. So, in the problem, you first solve the part inside the parentheses. Are there exponents? No, so we move on. Anything need to be multiplied? Yes, 20.3 x 0.7. That gives us 14.21. Now, there is nothing left in the parentheses to be divided, added, or subtracted, so we move on to the outside. We multiply 14.21 by 7 and get 99.47.
Start with parenthesis.
20.3 * 0.7 = 14.21
14.21*7 = 99.47
Answer: 99.47
20.3 * 0.7 = 14.21
14.21*7 = 99.47
Answer: 99.47
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