Morgan has 1/3 of a pond of bottle caps storend evenly in 3 boxes. How many pounds of bottles caps are in each box?

Answers

Answer 1

Answer: 1/6 is the answer 1/3 time 1/3= 1/6

Related Questions

Two times the least of three consecutive odd integers exceeds three times the greatest by 15
If you are given the measurements of two sides of a triangle, what will be true about the triangles you make?
8. Karyn proofreads 15 pages in 2 hours for $40.a. What is her proofreading rate in pages per hour? b. How much does she receive on average for a page? if able answer both also its Rate (unit rate's possilbe)
The price of 8.4 oz of orange juice is $2.42. What is the unit price
320= how many hundreds/ones? You get Thanks

What is the smallest number with the factors 1,2,3,4, and 5? What is the special name for it?

Answers

to find LCM
factor and eliminate ones already represented
1=1
2=2
3=3
4=2*2
5=5

1*2*2*3*5=60

A submarine can descend at a rate of -2.5 meters/second. Suppose that the submarine begins at a depth of -25 meters. How long would it take the submarine to reach its maximum depth of -200 meters?_________________

Answers

The distance from the initial depth to the maximum depth is:
abs (-200- (-25))= 175 m (distance is always >=0, so we have to take the abs).

175 m* (1 sec/ 2.5m)= 70 sec.

It would take the submarine 70 seconds to reach its maximum depth.

Hope this helps~

The half-life of a radioactive kind of lanthanum is 93 minutes. How much will be left after 279 minutes, if you start with 2,064 grams of it?

Answers

easy just subtract 2,064by 279

2,064- 279 that's what i thing the answer is sorry for answering so late .

Tomas correctly spelled 18 out of 20 words oh his last spelling quiz. What decimal represents the portion of the words that Tomas spelled correctly?

Answers

The decimals that represent the portions of the words that Tomas spelled correctly is 0.9 or 0.90.

18/20 and put it on ?/10 which is 9/10. so 0.90

Use vertical multiplication to find the product of: $x ^(3) + 2x + 3 * x ^(3) - x + 1$

Answers

Answer:

$x^6+x^4+4x^3-2x^2-x+3$

Step-by-step explanation:

$x^3+2x+3$

$*(x^3-x+1)$

---------------------------------

First step multiply your terms in your first expression just to the 1 in the second expression like so:

$x^3+2x+3$

$*(x^3-x+1)$

---------------------------------

$x^3+2x+3$ Anything times 1 is that anything.

That is, $(x^3+2x+3) \cdot 1=x^3+2x+3$ .

Now we are going to take the top expression and multiply it to the -x in the second expression. $-x(x^3+2x+3)=-x^4-2x^2-3x$ . We are going to put this product right under our previous product.

$x^3+2x+3$

$*(x^3-x+1)$

---------------------------------

$x^3+2x+3$

$-x^4-2x^2-3x$

We still have one more multiplication but before we do that I'm going to put some 0 place holders in and get my like terms lined up for the later addition:

$x^3+2x+3$

$*(x^3-x+1)$

---------------------------------

$0x^4+x^3+0x^2+2x+3$

$-x^4+0x^3-2x^2-3x+0$

Now for the last multiplication, we are going to take the top expression and multiply it to x^3 giving us $x^3(x^3+2x+3)=x^6+2x^4+3x^3$ . (I'm going to put this product underneath our other 2 products):