Solving for z, we get → z = .
We have the following equation -
We have solve for z.
Solving this we will get -
βx - ax =
x(β - a) =
x =
According to the question, we have -
⇒
⇒ 5y = 2(z + 1)
⇒ = z + 1
⇒ z = - 1
⇒ z =
Hence, after solving for z, we get → z =
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Answer:
Parallel
Step-by-step explanation:
orthogonal: dot product of u times v= 0 degrees
utimesv= 7x21+2x6=147+12=159
Parallel: cos (u,v)=1
cos (u,v)=(u·v)/ IuI·IvI
cos (u,v)= 159/ (sqrt 7^2+2^2)·(sqrt 21^2 +6^2)
159/(sqrt 49+4) ·(sqrt 441+36)
159/(sqrt 53)·(sqrt 477)=
159/159
=1; therefore it is parallel
Answer:
5..
Step-by-step explanation:
How much did it rain on
both days?
30 points
Answer:
98 inches
Step-by-step explanation:
54inches + 44inches =
5 + 4 = 9
4 + 4 = 8
So... the answer is 98 inches?
I hope this helps!!
wide has a semicircle cut out of it.
Find the area of the paperboard that remains. Use the value 3.14
for π, and do not round your answer. Be sure to include the correct unit in your answer.
Answer:
The remaining area of the paperboard is 363 square inches.
Step-by-step explanation:
The length of the rectangular board = 26 inches
The width of the rectangular board = 20 inches.
Now, the area of the board = square inches
Now, a semicircle has been cut out of it.
Let is assume that the diameter of the semicircle be 20 inches.
So, radius will be = 10 inches
Area of semicircle is =
So, we get : Area =
= 157 square inches.
Now after cutting the semi circle, the area remained = square inches.
Therefore, the remaining area of the paperboard is 363 square inches.
Answer:
See below.
Step-by-step explanation:
Find the area of the rectangle using A = l*w = 26*20 = 520.
Now find the area of the semi circle using A = 1/2 πr². Since the instructions do not say the diameter of the semi circle assume it is 20 or 26.
If it is 20: r = 10 and the area is A = 1/2 π10²=50π = 157.
If it is 26: r = 13 and the area is A = 1/2π13² = (84.5)π = 265.33.
The area of the paperboard that remains will be the area of the rectangle minus the area of the semi circle.
If the diameter of the semi circle is 20 then 520 - 157 = 363.
If the diameter of the semi circle is 26 then 520 - 254.67.