The first term is 4 and the rule is add 15 then subtract 10

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Answer 1

Answer:

Is this what you were looking for?

4 + 15 - 10, because that would make 9

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LMNP is a rectangle. Find the value of x and the length of each diagonal.
LN = 5x + 19 and MP = 8x - 8
x=0

Answers

Question:

LMNP is a rectangle. Find the value of x and the length of each diagonal.

LN = 3x + 1 and MP = 8x – 4

Answer:

Value of x = 9, Length of LN = 64, Length of MP = 64

Solution:

Given LMNP is a rectangle. LN and MP are diagonals.

LN = 5x + 19 and MP = 8x – 8

Diagonals of a rectangle are equal in length.

⇒ LN = MP

⇒ 5x + 19 = 8x – 8

Combine like terms together.

⇒ 19 + 8 = 8x – 5x

⇒ 27 = 3x

Divide by 3 on both sides of the expression, we get

⇒ x = 9

The value of x is 9.

To find the length of the diagonals.

LN = 5(9) + 19

= 45 + 19

LN = 64

MP = 8(9) – 8

= 72 – 8

MP = 64

Length of LN = 64 and the length of MP = 64.

Describe the trend in the scatter plot.-not enough information because the trend line is unclear

-positive correlation

-negative correlation

-no correlation

Answers

Answer:

Step-by-step explanation:

positive correlation

Help me out please???? <3

Answers

Answer:

Step-by-step explanation:

100 / 5 = 20

The answer would be 20.

10^2/ 5^1
10^2= 100 & 5^1 = 5
100/5= 20

The standard normal curve shown here is a probability density curve for a continuous random variable. This means that the area underneath the entire curve is 1. What is the area of the shaded region between the two z-scores indicated in the diagram?

Answers

Answer with explanation:

The Curve given here is a probability density curve for a continuous random variable.

Area under the entire region of the curve = 1

Using the Standard normal table to obtain area occupied when Z values are given

Area of the normal curve, when ,Z =0.88, is =0.8106

Area occupied by normal curve ,when Z= -1.26, is =0.1038

So, Area of shaded Region

$Z_(0.88)-Z_(-1.26)=0.8106-0.1038\n\n=0.7068$

Option D:→ 0.7068

I used one of the statistical functions on my trusty TI-83 Plus calculator:

normcdf(-1.26, 0.88) = 0.707

Note that this is, as expected, between 0 and 1.

A number cube is rolled 360 times. And the results are recorded as follows: 54 ones, 60 twos, 66 threes, 71 fours, 35 fives, and 74 sixes. What is the experimental probability of rolling a two or a three? a) 0.15 b) 0.1 c) 0.35 d) 0.65