The concentration of ions in the solution is 0.0063 M
pH is a quantitative measure of the acidity or basicity of aqueous or other liquid solutions.
pH or pOH is the measure of acidity or alkalinity of a solution.
pOH is calculated by taking negative logarithm of hydroxide ion concentration.
pH = -log []
pH + pOH = 14
11.8 + pOH = 14
pOH = 2.2
Putting in the values:
2.2 =-log []
[] =0.0063 M
Hence, the concentration of ions in the solution is 0.0063 M
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[OH⁻] = 6.31 × 10⁻³ M
Step 1: Calculate pOH as,
pH + pOH = 14
As, pH = 11.8
So,
11.8 + pOH = 14
Or,
pOH = 14 - 11.8
pOH = 2.2
Step 2: Calculate [OH⁻],
pOH is related to [OH⁻] as,
pOH = - log [OH⁻]
Putting value of pOH,
2.2 = -log [OH⁻]
Solving for [OH⁻],
[OH⁻] = 10⁻²'² ∴ 10 = Antilog
[OH⁻] = 6.31 × 10⁻³ M
B. newton.
C. gram.
D. nanometer.
The freezing point of lead is 621.5 fahrenheit (327.5 celsius). The freezing point is the temperature at which a substance transitions from its liquid to its solid state, typically under normal atmospheric pressure.
The temperature at which a substance changes from its liquid phase to a solid phase, normally under normal atmospheric pressure, is referred to as the freezing point. It is a physical attribute of matter. This transition takes place when the attraction interactions between the substance's molecules outweigh their kinetic energy, leading the molecules to organise themselves in a predictable way and create a solid lattice. The nature of the substance, pressure, and contaminants in the substance are some of the elements that affect the freezing point. Different intermolecular forces of varying types and strengths give different substances different freezing points. Thefreezing pointof lead is 621.5 fahrenheit (327.5 celsius).
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Answer: Option (1) is the correct answer.
Explanation:
A redox reaction is a reaction in which both oxidation and reduction takes place.
For example,
Oxidation-half reaction :
Reduction-half reaction :
Hence, we can see that electrons are involved in a redox reaction.
Therefore, we can conclude that in a redox reaction, electrons are the particles which are lost and gained in equal numbers.
0.500 mole of any gas at standard temperature and pressure (STP) is equivalent to 11.2 liters. This is calculated using Avogadro's Law.
The quantity that represents 0.500 Mole at Standard Temperature and Pressure (STP) refers to the volume of gas. According to Avogadro's law, which states that equal volumes of gases at the same temperature and pressure contain an equal number of molecules, 1 mole of any gas at STP occupies a volume of 22.4 liters. Therefore, 0.500 mole of a gas at STP would occupy a volume of 11.2 liters.
Here's how you calculate this: Use Avogadro's law proportion, which is V1/n1 = V2/n2. Given n1 is 1 mole, V1 is 22.4 liters (which are standard values at STP) and n2 is 0.500 mole (your desired quantity), you can solve for V2 :
V2 = V1 * n2 / n1 = 22.4 L * 0.500 mol / 1 mol = 11.2 L.
So, 0.500 mole of any gas at STP would have a volume of 11.2 liters.
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