Answer:
A bond is formed and energy is released.
Explanation:
Given a reaction equation, the elements which we have on the left side of the arrow are called the reactants and the elements which we have on the right side are called the products.
In this exercise, the reactants are N(g) and N(g) and the products N2(g) and energy.
After the reaction took place, N(g) and N(g) disappeared and instead N2(g) was formed. We can conclude that a bond was formed between both N(g).
Also, in the products certain amount of energy was released (because we have it on the products side)
The correct option is ''A bond is formed and energy is released''
1. Color comparison
Il. Taste comparison
III. Boiling Test
iv.
Melting Test
Answer:
boiling test or melting test
Explanation:
and what is it main function?
Will mark as Brainliest✅
Cf, the element has the following mass spectrum. Therefore, option (D) is correct.
California (Cf) is a radioactive element with a complicated mass spectrum that shows its isotopic makeup and decay trends. Peaks in Cf's mass spectrum denote isotopes with differing mass-to-charge ratios. These peaks signify isotopes, which are elemental atoms with varying neutron counts.
The mass spectrum yields important information about the sample's isotope abundance and masses. Researchers can determine Cf's isotopic distribution and nuclear characteristics like decay modes and half-lives by analyzing peaks and intensities. This is crucial since Cf's radioactivity and prospective uses in nuclear research and medicine are vital.
In conclusion, Californium's massspectrum reveals its isotopic makeup and behavior, helping researchers understand its characteristics and uses. Therefore, option (D) is correct.
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the answer is cf that the answer
Scientists would deal with the aspect of cloning a particular gene into a bacterium or making of hybridoma cells that will produce the particular required protein. Engineers will then design and develop a bioreactor which is a programmed instrument that avails the required substances to the cells/bacteria in specific amounts and at particular time periods to grow and reproduce the cells in large amounts.
b. transition metals
c. inner transition metals
d. groups 1A and 2A
Answer : The correct option is, (a) Groups 3A through 8A
Explanation :
The general electronic configurations of :
Group 1A :
Group 2A :
Group 3A :
Group 4A :
Group 5A :
Group 6A :
Group 7A :
Group 8A :
Transition metal :
Inner transition metal (Lanthanoids) :
Inner transition metal (Actinoids) :
From the general electronic configurations, we conclude that the groups 3A through groups 8A elements that are characterized by the filling of p-orbitals.
Elements that are characterized by the filling of p orbitals are classified as .
Further Explanation:
In order to make the study of numerous elements easier, these elements are arranged in a tabular form in increasing order of their atomic numbers. Such a tabular representation of elements is called a periodic table. Horizontal rows are called periods and vertical columns are called groups. A periodic table has 18 groups and 7 periods.
a. Groups 3A through 8A
The elements from group 3A to 8A has the general outermost electronic configuration of . So the added electrons are to be filled in p orbitals.
b. Transition metals
These metals have the general valence configuration of . This indicates that the added electrons enter either s or d orbitals.
c. Inner transition metals
These are classified as lanthanoids and actinoids. The general outermost configuration of lanthanoids is while that of actinoids is . In both cases, the added electron enters either d or f orbitals.
d. Groups 1A and 2A
The elements of group 1A have the general valence electronic configuration of . It implies the last or valence electron enters in the s orbital. The group 2A elements have a general configuration of . Here also the last electron enters the s orbital.
So elements from groups 3A to 8A are classified by the filling of p orbitals and therefore option a is correct.
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Answer details:
Grade: High School
Subject: Chemistry
Chapter: Periodic classification of elements
Keywords: periodic table, configuration, ns1, ns2, d, p, f, 3A, 8A, transition metals, inner transition metals, lanthanoids, actinoids, orbitals, 1A, 2A.
Answer:0.7989883138766937
Explanation: