If a magnet is cut in paris what will be its north and south pole

Answers

Answer 1

Answer: When carried out in Paris, the procedure will produce the same results as in
Stockholm, Copenhagen, Rome, or Madrid. There is no reason to expect a
different outcome in any other world capital.

Answer 2

Answer: When a magnet is cut into two parts, then both parts will have a south and north pole because magnetic fields lines are continuous and always formed closed loops.

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The Pangaea theory supports the theory of plate tectonics because _____.it is based on the idea that there were several land masses when Earth was first createdit is based on the idea that all the present continents were one supercontinentit does not require scientists to support the notion that Earth's plates can moveone day, Earth will have one large land mass again

How much work is required to turn an electric dipole 180° in a uniform electric field of magnitude E = 46.0 N/C if the dipole moment has a magnitude of p = 3.02 × 10−25 C·m and the initial angle is 64°?

Answers

Answer:

$W=1.22*10^(-23)J$

Explanation:

Torque and energy of an electric dipole in an electric field we find:

$W=U(\alpha_(o)+\pi )-U(\alpha_(o) )=-pE(cos(\alpha_(o)+\pi )-cos(\alpha_(o) ))\nW=2pECos\alpha_(o)\n W=2(3.02*10^(-25)C.m )(46.oN/C)Cos64\nW=1.22*10^(-23)J$

Final answer:

The work required to turn an electric dipole 180° in a uniform electric field is -4.89 × 10^-24 J.

Explanation:

To calculate the work required to turn an electric dipole 180° in a uniform electric field, we can use the formula:

W = -pE(1 - cosθ)

where W is the work done, p is the dipole moment, E is the electric field strength, and θ is the angle between the dipole moment and the electric field.

Plugging in the given values:

W = - (3.02 × 10-25 C·m)(46.0 N/C)(1 - cos(180° - 64°))

Simplifying the equation gives the work done to be -4.89 × 10-24 J.

Learn more about Work done on an electric dipole here:

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A crane has an arm length of 20m inclined at 30deg with the vertical. It carries a container of mass of 1 ton suspended from the top end of the arm. Find the torque produced by the gravitational force on the container about the point where the arm is fixed to the crane. Given: 1 ton = 1000 kg; neglect the weight of the arm. Hint: take the force and perpendicular distance from the point where the arm is fixed to the crane. Note: Express your answer in whole number. No unit is required for the final answer. Set your calculator in radians.

Answers

To find the torque produced by the gravitational force on the container, we need to calculate the force and perpendicular distance from the point where the arm is fixed to the crane.

First, let's calculate the force exerted by the gravitational force on the container. The weight of the container can be calculated using its mass and the acceleration due to gravity. Given that the mass of the container is 1000 kg (1 ton) and the acceleration due to gravity is approximately 9.8 m/s^2, we can calculate the force as follows:

Force = mass * acceleration due to gravity
Force = 1000 kg * 9.8 m/s^2
Force = 9800 N

Next, we need to find the perpendicular distance from the point where the arm is fixed to the crane to the line of action of the gravitational force. This distance can be determined using trigonometry.

The perpendicular distance can be calculated using the formula:

Perpendicular distance = arm length * sin(angle)

Given that the arm length is 20 m and the angle with the vertical is 30 degrees, we can calculate the perpendicular distance as follows:

Perpendicular distance = 20 m * sin(30 degrees)
Perpendicular distance = 20 m * 0.5
Perpendicular distance = 10 m

Now, we can calculate the torque using the formula:

Torque = force * perpendicular distance

Substituting the values we calculated earlier:

Torque = 9800 N * 10 m
Torque = 98000 Nm

Therefore, the torque produced by the gravitational force on the container about the point where the arm is fixed to the crane is 98000 Nm.

What is the focal length of a lens?A.
the distance between the object and the image
B.
distance between the object and the center of the lens
C.
the distance between the center of the lens and the image
D.
the distance between the focal point and the center of the lens

Answers

Answer is D.the distance between the focal point and the center of the lens.

Answer:

it is B i took the test and got it wrong when someone said it was A

Explanation:

it is the one that says the sizing of the objects will appear unusual

If the core of a supernova explosion contains three or more solar masses of matter, the core will most likely become a _____.

Answers

The correct answer to the question you gave above would be a black hole. If the core of a supernova explosion contains three or more solar masses of matter, the core will most likely become a black hole.

Car A has a mass of 1,200 kg and is traveling at a rate of 22 km/hr. It collides with car B. Car B has a mass of 1,900 kg and is traveling in the same direction at 25 km/hr. Which of the following statements is true?A) The momentum before the collision is equal to the momentum after the collision.

B) The momentum before the collision is greater than the momentum after the collision.

C) The momentum before the collision is less than the momentum after the collision.

Answers

The car A has a mass of 1200 kg.

The car B has the mass of 1900 kg.

It is given that velocity of car A is given as 22 Km/hr

The car B has the velocity of 25 Km/hr.

Let the mass of two bodies are denoted as $m_(1) \ and\ m_(2)$

Let the velocity of cars A and B are denoted as $v_(1) \ and\ v_(2)$

The momentum before collision is-

$p_(i) =m_(1) v_(1) +m_(2) v_(2)$

[Here p stand for momentum.]

We are asked to calculate the final momentum of the system after collision.

The answer of the question is based law of conservation of linear momentum.

As per law of conservation of linear momentum the sum total linear momentum for an isolated system is always constant.Hence irrespective of the type of collision[elastic and inelastic],the momentum of the system is always constant which is a universal truth.

Let after the collision the velocity of A and B are $v'_(1) \ and\ v'_(2)$

Hence the final momentum of the system is-

$p_(f) = m_(1) v'_(1) +m_(2) v'_(2)$

As per the law of conservation of linear momentum, the initial and final momentum must be equal i.e

$p_(i) =p_(f)$

$m_(1) v_(1) +m_(2)v_(2) =m_(1) v'_(1) +m_(2) v'_(2)$

Hence the option A is right.

A
This principle is known as the law of conservation of momentum.

If the contents of a cell have a solute concentration of 0.04 percent which of these solutions would cause it to swell? A.) 10-percent solute concentration B.) 1-percent solute concentration C.) 0.1 percent solute concentration D.) 0.01 percent solute concentration.

Answers

If the contents of a cell have a solute concentration of 0.04 percent, the solution that would cause it to swell is D) 0.01 percent solute concentration.

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