Answer:
x = 3.5
Step-by-step explanation:
A.1/3
B.1
C.2/5
D.6/225
Carson drove a distance of 120120120 kilometers. He initially had 303030 liters of fuel, and his car's fuel efficiency is 100100100 cubic centimeters per kilometer.
What calculation will give us the estimated volume of fuel that remains in Carson's tank by the end of the drive, in liters?
Answer:
Step-by-step explanation:
The formula for the remaining volume of fuel in a car's tank is expressed as;
V = I - E.D
where;
I is the initial volume of fuel,
E is the fuel efficiency, and;
D is the distance traveled.
Given
I = 30 litres
1m³ = 1000L
x = 30L
x = 30/1000
x = 0.03m³
I = 0.03m³
E = 100cm³/km
E = 100*10^-6m³/km
E = 10^-4m³/km
E = 10^-4m³/1000m
E = 10^-7m²
D = 120km
Convert km to metres
D = 120km = 120,000m
Substitute the results into the formula;
V = I - E.D
V = 0.03 - (10^-7)(120,000)
V = 0.03 - 0.012
V= 0.018 m³
Convert 0.018 m³ to litres
Since 1 m³ = 1000L
0.018 m³ = y
cross multiply;
y = 1000 * 0.018
y = 18 litres
Hence volume of fuel that remains in Carson's tank by the end of the drive is 18 litres
The probability that a worker chosen at random works at least 8 hours is 0.84
At least 8 hours simply means 8 hours and above
Thus, the probability of at least 8 hours can be obtained as illustrated below:
P(At least 8 hours) = P(8) + P(9) + P(10)
P(At least 8 hours) = 0.61 + 0.15 + 0.08
P(At least 8 hours) =0.84
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