Tanx cosx = 0

15 POINTS!

Answers

Answer 1

Answer: $tanx\ cosx=0;\ \ \ \ D:x\neq(\pi)/(2)+k\pi;\ (k\in\mathbb{Z})\n\ntanx* cosx=0\iff tanx=0\ \vee\ cosx=0\n\ntanx=0\iff x=k\pi\n\ncosx=0\iff x=(\pi)/(2)+k\pi\notin D\n\nSolution:x=k\pi\ (k\in\mathbb{Z})$

Answer 2

Answer: Tan = sin / cos./ / / Tan cos = (sin/cos) cos = sin = 0 / / / x = any multiple of 180 degrees.

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What is the sum of the geometric series 2^0 + 2^1 + 2^2 + 2^3 + 2^3 + 2^4 + … + 2^9?

Answers

the nth term is
an=a1(r)^(n-1)
an=1(2)^(n-1)
a1=1
r=2

the sum of a geometric seequence is
$S_(n)=(a_(1)(1-r^(n)))/(1-r)$
a1=1
r=2
we want to find $S_(10)$ (since we minus 1, the highest exponet is 9 so add 1 to make it correct)

$S_(10)=(1(1-2^(10)))/(1-2)$
$S_(10)=((1-1024)/(-1)$
$S_(10)=((-1023)/(-1)$
$S_(10)=1023$

Hello,

$1+2+2^2+2^3+...+2^9=(2^(10)-1)/(2-1)=1023$

Pls help me with this question!!!

Answers

Answer:a:20 thats the one

Step-by-step explanation:

Someone please help me, I’m struggling :(

Answers

Answer:

constant

Step-by-step explanation:

Since this is a horizontal line the slope is zero

This means the graph is constant

Answer:

constant because it isn't going up or down, just moving straight

Step-by-step explanation:

How many numbers between 200 and 400 meet one or both of the conditions given in the two statements below?Statement 1: The number begins with 3
Statement 2: The number ends with 3

Answers

There are 100 numbers that begin with 3. In the other 200, there are effectively a tenth ending in 3. That is, 120 total numbers.

Write the equation For a Line that intersects points(1,3) And (2,5) which one is a.y=x+2 B.y=2x+1. C.y=3x-3. D.Y=-x+3 For me is letter B.please help

Answers

$(1,3) ,\ \ (2,5) \n \n \n First \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \n \n m= (y_(2)-y_(1))/(x_(2)-x_(1) ) \n \nm=(5-3)/(2-1) = (2)/(1)=2 \n \nNow \ use \ y = mx + b \ with \ either \ point \ to \ find \ b, \ the \ y-intercept \ : \n \n y=mx+b \n \n3=2 \cdot 1+b\n \n3= 2 +b \n \nb=3-2=1 \n \n y=2x+1 \ is \ the \ answer \ B$