The sum of two numbers is 40, and their difference is 8. Find the numbers.

Answers

Answer 1
Answer: x+y=40\n x-y=8\n -----\n 2x=48\n x=24\n\n 24+y=40\n y=16
Answer 2
Answer:    a - b = 8
+ a + b = 40   
   2a = 48
     a = 24

a - b = 8
24 - b = 8
b = 16

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Use the REMAINDER THEOREM to explain whether or not (x-2) is a factor of F(x)=x^4-2x^3+3x^2-10x+3

Answers

(P(x))/(R(x))|(D(x))/(Q(x))

\frac{x^4-2x^3+3x^2-10x+3}{}|\frac{x-2}{}

(x^4-2x^3+3x^2-10x+3)/(-x^4+2x^3)|(x-2)/(x^3)

(3x^2-10x+3)/(-3x^2+6x)|(x-2)/(x^3+3x)

(-4x+3)/(4x-8)|(x-2)/(x^3+3x-4)

\frac{-5}{}|(x-2)/(x^3+3x-4)

\boxed{\boxed{(x^4-2x^3+3x^2-10x+3)/(-5)|(x-2)/(x^3+3x-4)}}

R(x)=-5

Consider the following pair of equations: y = 3x + 3
y = x − 1

Explain how you will solve the pair of equations by substitution. Show all the steps and write the solution in (x, y) form.

Answers

The coordinate (x,y)=(-2,-3).

We have given the  following pair of equations

y = 3x + 3.....(1)

y = x − 1.....(2)

Here we use the substitution method

What substitution method?

The value of one variable from one equation is substituted in the other equation

So the given system of linear equation

We have substitute the value of y from equation 2 into the value of y in equation one

So we get

x − 1= 3x + 3

add like terms

x-3x=3+1

-2x=4

x=4/-2

x=-2

Plug x=-2 in equation 2 we get,

y = -2 − 1

y=-3

Therefore we get the coordinate(x,y)=(-2,-3).

To learn more about the substitution method visit:

brainly.com/question/22340165


3x + 3 = x - 1 \n 3x - x =   - 1 - 3 \n 2x =  - 4 \n x =  ( - 4)/(2 )  =  - 2
Take X=-2 into y
y = x - 1 \n y =  - 2 - 1 \n y =  - 3
(x, y) =(-2,-3)

What is the distance between points A and B? please help!! WILL MARK BRAINLIEST!!!!

A. 29
B. 2 V 29
C. 3 V 14
D. V58

Answers

Answer:

The answer should be 7.615773...

or \sqrt58

Step-by-step explanation:

\sqrt(x^(2) -x^(1) )^(2) +(y^(2) -y^(1) )^(2) \n\n\n\sqrt(11^(2) -4^(1) )^(2) + (7^(2) - 4^(1) )^(2)\n\n \n\sqrt58 = 7.61577310586...\n

I hope this helps.

Write a fraction for 2 copies of 1/6

Answers

1/6 = 2/12 = 3/18

multiply or divide the top bottom numbers by the same number

Find the approximate value of the circumference of a circle with the given radius. Use = 3.14. Round your answer to the nearest hundredth.5.1 cm

how do you now what to mutliply by like 5.1 x 5.1 the multiply by 3.14

Answers

In solving for the value of the circumference of the circle we will just the formula c = πr². From that we will substitute the value c = (3.14)(5.1)², which is equal to c = 3.14 (26.01), which will be then c = 81.6714. In presenting the answer to nearest hundredth it would be 81.67 cm

For the given 4×4 gray level image below: Filter the image by a) 3×3 average filter using zero padding b) Laplacian filter with the given mask w d

=




0
1
0


1
−4
1


0
1
0




Answers

Answer:

Step-by-step explanation:

a) To filter the given 4x4 gray level image with a 3x3 average filter using zero padding, follow these steps:

1. Apply zero padding to the image by adding an extra layer of zeros around the edges. This ensures that the filter can be applied to all pixels, including those at the image borders.

2. Place the 3x3 average filter over each pixel in the image, centered on that pixel.

3. Multiply the corresponding filter coefficients with the pixel values within the filter region and sum them up.

4. Divide the sum by the total number of coefficients in the filter (which is 3x3 = 9 in this case) to get the average value.

5. Replace the original pixel value with the computed average value.

6. Repeat steps 2-5 for all pixels in the image.

b) To filter the given 4x4 gray level image with the Laplacian filter using the given mask:

1. Place the Laplacian filter mask over each pixel in the image, centered on that pixel.

2. Multiply the corresponding mask coefficients with the pixel values within the filter region and sum them up.

3. Replace the original pixel value with the computed sum.

4. Repeat steps 1-3 for all pixels in the image.

The resulting image will be the filtered output, where each pixel has been modified according to the chosen filter method.