Rewrite without rational exponents, and simplify, if possible.. (x^4y^4) ^1/3








Answers

Answer 1
Answer: \left(x^4y^4\right)^(1)/(3)=x^{4\cdot(1)/(3)}y^{4\cdot(1)/(3)}=x^(4)/(3)y^(4)/(3)=x^{1(1)/(3)}y^{1(1)/(3)}=x^{1+(1)/(3)}y^{1+(1)/(3)}=x^1x^(1)/(3)y^1y^(1)/(3)\n\n=x\sqrt[3]{x}\cdot y\sqrt[3]y=xy\sqrt[3]{xy}
Answer 2
Answer: That would become (XY)^4/3 . The exponent is still rational. Sorry.

Related Questions

There are 50 rabbits on a farm. They are increasing at the rate of 12% every month. How many months will it be until there are 1000 rabbits?
Which function describes the graph in the picture? NEED HELP ASAP
Rathan thinks all factors of even numbers are even. Which explains whether Rathan is correct? He is correct because the product of 2 and any number is even. He is correct because the product of two even numbers is even. He is incorrect because the product of an even number and an odd number is even. He is incorrect because the product of two odd numbers is odd
What is the value of f(2)A) -1B) -0.75C) 3D) 12
Which of the following is the same as 2.3 x 10³

what would be an outlier if added to the data set below? 507, 586, 499, 542, 615, 600, 561, 519 A.487 B.535 C.610 D.380

Answers

I am pretty sure the answer is F

How to find the perimeter and the area of a rectangle on a coordinate plane using the distance formula? : A(3,8) B(5,4) C(-4,-1) D(-6,3) Round to the nearest tenth if necessary.

Answers

I used some site to plot the points. 

First, let's recall the formulas for Perimeter and Area of a Rectangle.
Perimeter = 2(l+w)
Area = l×w
Also, the distance formula is
D = \sqrt{( x_(2)-x_(1))^2+{(y_(2)-y_(1))^2}

Now, we need to determine l and w.
So, the length is the distance of AD or BC
and the width is the distance of DC or AB
(I'll just use the sides that I've labelled for ease)

So first to determine the length, we need to calculate the distance of AD
Points are A(3,8) and D(-6,3) 
x_(1) =3, x_(2) =8, y_(1) =6, y_(2) =-3
D_(AD)= \sqrt{( 6-3)^2+{(-3-8)^2}
D_(AD)= √((3)^2+(-11)^2)
D_(AD)= √(9+121)
D_(AD)= √(130) ≈ 11.40
So the length of the rectangle is 11.40 units.

Now, the width!
So first to determine the width, we need to calculate the distance of DC
Points are D(-6,3) and C(-4,-1)
x_(1) =6, x_(2) =-4, y_(1) =-3, y_(2) =-1
D_(DC)= \sqrt{(-4-6)^2+{(-1- -3)^2}
<span>D_(DC)= \sqrt{(-4-6)^2+{(-1+3)^2}
D_(DC)= √((-10)^2+(2)^2)
D_(AD)= √(100+4)
D_(AD)= √(104) ≈ 10.20
So the width of the rectangle is ≈10.20 units.

Let's now solve for Perimeter and Area using
l = 11.40
w = 10.20

Perimeter = 2(l+w)
Perimter = 2(11.40+10.20)
Perimter = 2(21.60)
Perimter = 43.2 units

Area = l×w
Area = (11.40)(10.20)
Area = 116.28 
Area = 116.3 units² (rounding)

In conclusion, given points A(3,8) B(5,4) C(-4,-1) D(-6,3), the Perimeter is 43.2 units and the Area is  ≈116.3 units² using the distance formula. 

Use IDEAL to solve the following problems (WORTH 50 POINTS)15. A standard piece of paper is 8 1/2 in. by 11 in. What is the diagonal length of the piece of paper? Give the answer rounded to the nearest tenth.


16. Garrett's dad is making him help pour a concrete slab for a shed. The pad is a rectangle that has dimensions of 9 1/2 ft by 15 ft. He wants to measure diagonally to make sure the frame is a rectangle. What should the diagonal length of the frames be?

Answers

so pythagrorean theorem is the ideal way and easiest way to solve this

a^2+b^2=c^2

8.5^2+11^2=x^2
72.25+121=193.25
square root of 193.25=13.9014 or 13.9 in


9.5^2+15^2=x^2
90.25+225=315.25
square root of 315.25=17.7553 or 17.8 ft

How can you prove a conjecture is false?

Answers

The easiest way to disprove any conjecture is to find just one counterexample that invalidates the argument.

How do You find 20% of 40

Answers

Divide by 100% will cancel out the percent, then, multiply the value like so
(20)/(100) * 40=8

How to solve this problem

Answers

Since they are congruent, all will be the same value.

c = 3
∠d = 38°  (asked for the angle)
g = 5