The improper fraction 19/4, can be changed into a mixed number as: 19/4 = 4¾.
A mixed number is a combination of a whole number and a proper fraction.
To change the improper fraction 19/4 into a mixed number, follow these steps:
Step 1: Divide the numerator (19) by the denominator (4).
19 ÷ 4 = 4 with a remainder of 3.
Step 2: Write down the whole number part (the quotient) and the remainder as a fraction.
The quotient is 4, and the remainder is 3. So we have: 4¾.
Therefore, 19/4 as a mixed number is 4¾.
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The new hourly rate after a 2.5% raise will be $6.15.
The quantity of anything is stated as though it were a fraction of a hundred. A quarter of 100 can be used to express the ratio. Per 100 is what the term percent signifies. The symbol ‘%’ is used to symbolize it.
Suppose you earn $6 per hour at your part-time job. The new hourly rate is after a 2.5% raise.
Let x be the new hourly rate. Then the equation is given as,
x = $6 x (1 + 2.5%)
x = $6 x (1 + 0.025)
x = $6 x 1.025
x = $6.15
The new hourly rate after a 2.5% raise will be $6.15.
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Answer:
|2a + b| = 2√(3) + 1
Step-by-step explanation:
|a| = √(3)
|b| = 1
θ = 5π/6
For scalar vectors, A.B = |a|.|b|.cosθ
a
|2a| = 2*√(3) = 2√(3)
|2a + b| = 2√(3) + 1
Since we don't have to find the scalar or dot product, there's no need to use the formula requiring the angle between them
|2a + b| = 2√(3) + 1
Answer:
Length of the rectangle is = 8 inches.
Step-by-step explanation:
Given :
Area of square = Area of the rectangle
According to the question:
Length of the square be 'x'.
Its area = (Side)*(Side) = ...equation (i)
Length of the rectangle =
Width of the rectangle =
Area of the rectangle =Length * Width
⇒
⇒ ...equation (ii)
Equating both the equation as area of both the figure are equal.
⇒
⇒ ...subtracting both sides
⇒ ...dividing both sides with 2
⇒ inches
Plugging the value of x=4 in the length of the rectangle.
We have,
⇒
So the length of the rectangle = 8 inches.
Prove: EG bisects HF and HF bisects EG.
Answer:
Given : EFGH is a Parallelogram
Prove : EG Bisects HF , HF Bisects EG
Step-by-step explanation:
Proof
Check image below
Answer:
Given Parallelogram EFGH
EG bisects HF and HF bisects EG, if and only if both the diagnols have same mid point.
Step-by-step explanation:
Step 01:
Let
E be the point (a,b)
F be the point (a',b)
G be the point (a',b')
H be the point (a,b')
Step 02:
Now find mid points of EG and HF
mid point of EG = ( , ) and
mid point of HF = ( , )
Since addition is commutative, and they have the same mid-point, so they bisect each other.