MATHEMATICS HIGH SCHOOL

Devin has started a lawn care service. He will charge a mowing fee of $10 plus $3 per square yard of lawn. He also offers trimming service, at $8 plus $1 per yard of the perimeter. Using x for the length of the lawn and y for the width of the lawn which part of the expression 10+3xy+8+(2x+2y) represents the charge for the mowing?A. 8+(2x+2y)
B. (2x+2y)
C. 3xy
D. 10+3xy

Answers

Answer 1
Answer:

Answer:

Option D is correct.

Charge for the mowing = 10 + 3xy

Step-by-step explanation:

here, x represents the length of the lawn and y represents the width of the lawn.

\text{Area of lawn} = \text{length} * \text{width} = xy square yard

Perimeter of lawn = 2 (x+y) = 2x + 2y yard

As per the statement:

Devin has started a lawn care service. He will charge a mowing fee of $10 plus $3 per square yard of lawn.

then;

Charge for mowing = 10 + 3 \cdot \text{Area of lawn}

                               = 10 + 3xy

Also, he offers trimming service at $8 plus $1 per yard of the perimeter.

⇒ Trimming service =8 + 1 \cdot \text{Perimeter} = 8 + (2x +2y)

Therefore, from the expression: 10 + 3xy +8 + (2x+2y)

10 + 3xy represents the charge for the mowing.
Answer 2
Answer: Answer is D because he charge 10 $ mowing free +3 per square yard of lawn
lawn has dimensions:
x and y
Area= x*y=xy squar yard
so charge is 
10 +3*Area=10+3xy
 

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Solve for x in this equation log9 1/3=x

Answers

The work is shown in the attachment 

What is the solution for the following equation?
x^2-6x+9=11

Answers

make one side equal zero
minus 11 to both sides
x^2-6x-2=0
another quadratic equation

if you hahve
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^(2)-4ac} }{2a}

1x^2-6x-2=0
a=1
b=-6
c=-2

x=\frac{-(-6)+/- \sqrt{(-6)^(2)-4(1)(-2)} }{2(1)}
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x=(6+/- √(44) )/(2)
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aprox
x=6.31662 or -0.316625

What's the answer ? ..... ​

Answers

Answer:

B) 10m^3(m^3+2)

Step-by-step explanation:

Hope this helps
Answer: B.
Explanation: when you distribute 10m^3 and multiply it to just m^3, you add the exponents which would give you 10m^6 then 10m^3 multiplied by just 2 will give you 20m^3. Which all together will be the initial problem 10m^6+20m^3

Please help me with this! I would appreciate it :)

Answers

1. b. Commutative Property of Addition 
Reason: There is no multiplication used

2. a. 60
Reason: 36 + 24 = 60

3. b. 3d + 9
Reason: Simplification and combining like terms :)

4. b. 4,-1
Reason: Coefficients are the numbers in front of variables 

5. b. 36m + 9
Reason: Just use distributive property (multiply 9 into both terms inside parenthesis)

6. b. 95.488
Reason: b = 165.288 - 39.7 - 30.1

7. The question is cut off, unanswerable

8. c. 5a, -3a
Reason: Like terms are things you can combine. So technically the answers could be b. and c. but just go with c. because they have variables.

9. b. 16
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Best of luck to you!

What is .333 written in its simplest fraction form?

Answers

The simplest fraction form of 0.333 will be 333/1000 .

Given,

Decimal form: 0.333

Now,

To convert decimal form into fraction form,

When the decimals are to be removed from the decimal form we divide the number by 10 , 100 , 1000 depending on the place of decimal .

Here the decimal is placed after 3 places from right side .

Thus the division will be done of 1000 .

So,

0.333 = 333/1000

333/1000 is the simplest form as it can not be reduced further .

Thus the simplest form in fraction is 333/ 1000 .

Know more about fractions,

brainly.com/question/10354322

#SPJ6
.333 in simplest fraction form is 333/1000.

{\boxed{(333)/(1000)}

A certain solution contains 4.3 grams of salt per liter.How much salt is there in 11 liters of the solution?
Round your answer, if necessary, to the nearest tenth.

Answers

Answer:

47.3 grams

Step-by-step explanation:

Given: A solution contains 4.3 grams of salt per liter.

To find: Amount of salt in 11 liters of the solution

Solution:

Amount of salt in 1 liter of the solution = 4.3 grams

So, amount of salt in 11 liters of the solution = 11 × Amount of salt in 1 liter of the solution = 11 × 4.3 = 47.3 grams

Hence, 11 liters of the solution contains 47.3 grams of salt.

Answer: 47.3

Step-by-step explanation: Khan Academy
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