cos(A+B+C)=cosAcosBcosC-cosAsinBsinC-sinAcosBcosC-sinAsinBcosC
A.4y = 2x – 6
B.3x + 5y = 7
4x = 2y – 5
C.2y = 4x + 2
D.2x = 5y + 4
15y = 6x – 12
Answer : D
2x=5y+4
15y=6x-12
Solve 2x=5y+4 for x
Divide both sides by 2
2x/2=(5y+4)/2
x = 5/2 y +2
Substitute 5/2 y +2 for x in 15y=6x-12
15y= 6x-12
15y= 6(5/2 y +2 ) -12
Simplify both sides of the equation
15y=15y
Add -15y to both sides
15y-15y= 15y-15y
0=0
Hey Lily , I hope this help and if you have question(s) please let me know . Thanks
Answer:
37.5 miles
Step-by-step explanation:
h=4+32t-16t^2
1The arrow is fired with an initial upward velocity of 2 ft/s.
2The arrow is fired with an initial upward velocity of 4 ft/s.
3The arrow is fired with an initial upward velocity of 8 ft/s.
4 The arrow is fired with an initial upward velocity of 32 ft/s.
By definition, the equation of movement in its generic form is given by:
Where,
g: acceleration due to gravity
v0: initial speed
h0: initial height
The equation for the arrow is given by:
Then, according to the definition, the initial velocity of the arrow is:
Answer:
4 The arrow is fired with an initial upward velocity of 32 ft / s.
Answer:
It would take 90 hours to fill the pool.
Step-by-step explanation:
There is a mistake in the question so it is corrected below:
An inlet pipe on a swimming pool can be used to fill the pool in 40 hours. The drain pipe can be used to empty the pool in 45 hours. If the pool is 1/4 filled and then the inlet pipe and drain pipe are opened, how many more hours would it take to fill the pool?
Now, to find the hours would it take to fill the 1/4 pool.
Let the hours it take to fill the pool be
A swimming pool can be used to fill the pool in 40 hours.
So, the rate of filling the pool = .
As, given the drain pipe can be used to empty the pool in 45 hours.
Thus, the rate of draining the pool = .
According to question:
Using cross multiplication:
Dividing both sides by 20 we get:
Therefore, it would take 90 hours to fill the pool.