MATHEMATICS HIGH SCHOOL

The vertex of this parabola is at (4, -3). When the x-value is 5, the y-value is -6. What is the coefficient of the squared expression in the parabola s equation?

Answers

Answer 1
Answer: The\ vertex\ form:y=a(x-k)^2+h\n\nwhere\ (k;\ h)\ \ are\ coordinates\ of\ vertex\n------------------------\ny=a(x-4)^2-3\n\nthe\ point\ on\ parabola\ (5;-6)\nPut\ x=5\ and\ y=-6\ to\ equation:\n\na(5-4)^2-3=-6\na(1)^2=-6+3\na=-3\n\nAnswer:y=-3(x-4)^2-3=-3(x^2-8x+16)-3\n\n=-3x^2+24x-48-3=-3x^2+24x-51

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complete this series of number : 9=4, 21=9, 22=9, 24=10, 8=5, 7=5, 99=10, 100=7, 16=?, 17=?​

Answers

Answer:

16= 7 &

17= 9

Step-by-step explanation:

_ - 72 = 62 - 53

Fill in the missing number

Answers

71-9=62 62-9=53 53-9=44 so let’s subtract 9 from our most current number.35. 35-9=26 the up coming number in your sequence is 26

12y = 4x + 8
A=
B=
C=
Can someone please help!!

Answers

12y = 4x + 8

A = 12y -4x + 8

B = 8yx = 8

C = yx =8/8

=yx = 1

Which equation has an a-value of 1, a b-value of –3, and a c-value of –5?

Answers

Answer:

x^2-3x-5

Step-by-step explanation:

The standard quadratic equations are given in the form of

ax^2+bx+c

Comparing the values of a , b and c and putting a=1 , b=-3 and c=-5 in the equation we get our quadratic polynomial as

x^2-3x-5
c-b=-2a If that is a possibility.

Pls help me i dont know how to do this pls answer ASAP

Answers

Answer:

If it does not pass through the origin, or is anything other than linear, it is not proportional

1.) Non-proportional

2.) Proportional

3.) Non-proportional

4.) Non-proportional

5.) Proportional

6.) Proportional

7.) Non-proportional

10.) Non-proportional

11.) Non-proportional

Answer:

Step-by-step explanation:

N means Non-Proportional

P means Proportional

1.N

2.P

3.N

4.N

5.P

6.N

7.N

10.N

11.N

Find the distance between the two points in simplest radical form. The points given are (1,8) and (6,-4).​

Answers

Answer:

d = 13 units

Step-by-step explanation:

calculate the distance d using the distance formula

d = \sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2 }

let (x₁, y₁ ) = (1, 8 ) and (x₂, y₂ ) = (6, - 4 )

substitute these values into the formula for d

d = √((6-1)^2+(-4-8)^2)

  = √(5^2+(-12)^2)

  = √(25+144)

  = √(169)

  = 13 units
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