MATHEMATICS HIGH SCHOOL

A container at a paper clip factory holds 2.1*10^3 pounds of paper clips. There are 9.6*10^5 paper clips in the container. Find the approximate weight of each paper clip in ounces. (1 pound= 16 ounces) Show Your Work.

Answers

Answer 1
Answer:

Answer:

The approximate weight of each paper clip is 0.035 ounce.

Step-by-step explanation:

A container at a paper clip factory holds 2.1*10^3 pounds of paper clips.

= 2.1*1000=2100 pounds

There are 9.6*10^5 paper clips in the container.

= 9.6*100000=960000

Now we get that 960000 paper clips weigh 2100 pounds.

So, each paper clip will weigh = (2100)/(960000) = 0.0021875 pounds

And 1 pound = 16 ounces

0.0021875 pounds = 16*0.0021875 = 0.035 ounce

Hence, the approximate weight of each paper clip is 0.035 ounce.
Answer 2
Answer: Divide the total weight (2.1 * 10^3 lbs.) by the total quantity of things (9.6 * 10^5) to get the lbs./paperclip. 

Then, multiply that number by 16 to get ounces/paperclip.

Related Questions

-3x^2+4x+5 what are the step to finding this answer?
HELPPSKSKSJDJJSJSnsnsks
What’s the triangle congruence shortcut
If f(x) = x and g(x) = 2, what is (f o g)(x)? 2x 2 x + 2 x/2
The slope of a speed-time graph indicatesa. acceleration. b. speed. c. direction. d. velocity.

What is the area of the trapezoid?8 m
110 m
12 m
80 m2
96 m2
100 m2
120 m2​

Answers

Answer:

100

Step-by-step explanation:

the formula is b1+b2 divided by 2 times the height. 8+12=20 divided by 2 is 10 times 10 is 100.

Answer:

I think the answer is 96

Step-by-step explanation:

I think that u have to multiply eight times ten. The you add twelve and that is how I got the answer of 96. I am pretty sure that it is correct but just i case I am sorry if u don't get it right.

Question 2(Multiple Choice Worth 4 points)(02.01 LC)
Figure EFGHK as shown below is to be transformed to figure E'F'G'H'K' using the rule (x, y) (x+8, y + 5):

Answers

Answer:

H' (4, 8 )

Step-by-step explanation:

the transformation rule (x, y ) → (x + 8, y + 5 )

means add 8 to the original x- coordinate and add 5 to the original y- coordinate, then

H (- 4, 3 ) → H' (- 4 + 8, 3 + 5 ) → H' (4, 8 )

Help me please I don't get it

Answers

Hey Dude Armando Is Correct!

A salesperson at a clothing store earns a 2% commission on all sales. How much commission does the salesperson earn on a $300 sale?

Answers

1 \% = (1)/(100)\n \n2 \% = 2 \cdot (1)/(100 )=(1)/(50) \n \n 300 \$ \cdot 2 \% = 300 \cdot (1)/(50 )= (300)/(50)=6 \% \n \n Answer : \ salesperson \ earns \ \$ \ 6

PLEASE HELP I'LL GIVE YOU 23 POINTSTHERE IS A SCREEN SHOT BUT JUST IN CASE YOU CANT ACCESS IT I'LL ADD THIS!
In the figure shown, line AB is parallel to line CD.

Part A: What is the measure of angle x? Show your work. (5 points)

Part B: Explain how you found the measure of angle x by identifying the angle relationships that you used along the transversal. (5 points)

AB and CD are parallel lines, and PQ and PR are transversals which intersect AB at P and CD at Q and R. Angle APQ is labeled as 65 degrees, angle QPR is equal to x, angle PRD is equal to 120 degrees.

Answers

Answer:

x = 55

Step-by-step explanation:

to find angle BPR you would do:

180 - 120 = 60

so BPR is 60°

now to find x you do this:

65 + 60 + x = 180

125 + x = 180

x = 55

Answer:

45 degrees

Step-by-step explanation:

pretty sure

A⁴+b⁴=a²b² ,prove that a⁶+b⁶=0

Answers

a^4+b^4=a^2b^2\n a^4-a^2b^2+b^4=0\n a^4-2a^2b^2+b^4+a^2b^2=0\n (a^2+b^2)^2=-a^2b^2

The only possible option is that a^2+b^2=0 \wedge a^2b^2=0\n and this condition is met only when a=0 \wedge b=0.

0^6+0^6=0\n 0=0
Other Questions
Of the flowers on Jill's front lawn,2/5 are tulips. Of the tulips,5/8 are yellow. What fraction of the flowers on Jill's front lawn are yellow tulips. A 18 B 1/4 C 1/2 D 7/13
Divide £42 in a ratio of 4:6
Parallel and Perpendicular Linesdetermine value of x for which a || b if m3=10x and m5=12x-25
It takes Doug 3 days to reroof a house. If Doug's son helps him, the job can be completed in 2 days. How long would it take Doug's son, working alone, to do the job?