A blue-light photon has a wavelength of4.80 × 10^−7 meter. What is the energy of the
photon?
(1) 1.86 × 10^22 J (3) 4.14 × 10^−19 J
(2) 1.44 × 10^2 J (4) 3.18 × 10^−26 J
Answers
Energy = （6.626 x 10^-34*3.00 x 10^8)/（4.80 × 10^−7）= 4.14*10^-19 J, which is 3.
Normally, when solving these equations, don't forget to check the units are correct (eg. wavelength is in meters) and dont forget to include the units in the calculation.
Taking into account the definition of photon, energy of a photon, wavelength, frecuency and propagation speed, the correct answer is the option (3): The energy of a photon with aa wavelength of 4.80×10⁻⁷ meter is 4.14×10⁻¹⁹ J.
What is a photon and energy of a photon
You have to know that electromagnetic radiation carries energy, which can be absorbed or emitted. To explain the processes of emission and absorption, Plank and Einstein proposed that the energy of radiation is composed of indivisible units (quanta). In each elemental process only a quantum of light can be emitted or absorbed. Each of these quanta was called a "photon".
The exchanges of energy between matter and radiation take place not continuously, but by discrete and indivisible quantities or quanta of energy. The quantum of energy is proportional to the frequency of radiation.
The relationship between the amount of energy (E) transported by the photon and its frequency (f) is determined by the following expression, where the energy of a photon is obtained by multiplying Planck's constant h by the frequency f of electromagnetic radiation:
E=h×f
What is wavelength, frecuency and propagation speed
Wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).
On the other side, frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).
Finally, the propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement.
The propagation speed relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation:
v = f×λ
All electromagnetic waves propagate in a vacuum at a constant speed of 3×10⁸ m/s, the speed of light.
What is the energy of the photon in this case
In this case, you know:
- h= 6.63*10⁻³⁴ Js
- f= v÷λ where v= 3×10⁸ m/s and λ=4.80×10⁻⁷ m
Replacing in the definition of energy of a photon:
E=h× (v÷λ)
E= 6.63×10⁻³⁴ Js× (3×10⁸ m/s ÷4.80×10⁻⁷ m)
Solving:
E= 4.14×10⁻¹⁹ J
Finally, the correct answer is the option (3): The energy of a photon with aa wavelength of 4.80×10⁻⁷ meter is 4.14×10⁻¹⁹ J.
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definition of photon and energy of a photon:
wavelength, frecuency and propagation speed:
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Galileo Galilei
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Edwin Hubble
Georges Lemaître
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Answers
Galileo Galilei was the first to use a telescope to observe the planets
Albert Einstein built a model of the universe based on relativity
Henrietta Swan Leavitt demonstrated a method to calculate the distance of celestial bodies
Edwin Hubble showed that the universe was expanding
Georges Lemaître theorized that the universe had a beginning
What is science?
Science is the methodical, empirically-based pursuit and application of knowledge and understanding of the natural and social worlds.
A method of learning about the world is science. Science allows people to participate in the creation of new knowledge as well as use that knowledge to further their goals. It is both a process, a product, and an institution.
Thus, The first person to observe the planets through a telescope was Galileo Galilei.
Based on relativity, Albert Einstein created a model of the universe.
A technique to determine the separation between celestial bodies was demonstrated by Henrietta Swan Leavitt.
Edwin Hubble demonstrated the expansion of the universe
According to Georges Lemaître, the universe had a beginning.
Learn more about the science here
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Answer:
Georges Lemaître - theorized that the universe had a beginning
Albert Einstein - huit a model of the inverse haced on relativity
Galileo Galilei - was the first to use a telescope to observe the planets
Edwin Hubble - showed that the universe was expanding
Henrietta Swan Leavitt - demonstrated a method to calculate the distance of celestial bodies
is my choices report if wrong
c. symbolic form
b. the forefront
d. positive space
Answers
Answer:
D. Positive space
Step-by-step explanation:
We are given that,
'Objects in a composition occupy ___'.
We know that,
In a composition the space occupied by the given object is known as the positive space, whereas any space around the object is known as the negative space.
So, we get that,
Objects in a composition occupy positive space.
Thus, option D is correct.
A. 3 m/s west
B.3 m/s east
C. 19 m/s west
D. 19 m/s east
Answers
its velocity is 3 m/s east.
Velocity is (displacement) / (time)
and Displacement is the distance between the start point and
end point, no matter what route was traveled between them.
In this case, the displacement is 15 meters east.
So the velocity is
(15 meters east) / (5 sec) = 3 meters/sec east .
Answer:
i dont know what he said but i think C
Explanation:
Answers
Question 1: (9-6)/(2-7)=-3/5
Question 2: (5-17)/(29-9)= -12/20, which simplifies to -3/5
Answer:
Explanation:
Answers
Final answer:
The distance between the charges is calculated using Coulomb's Law and found to be 0.134m or 13.4 cm.
Explanation:
This problem can be solved using Coulomb's Law. The formula for Coulomb's Law is: F = k*(|q1*q2|)/r², where F is the force between the charges, q1 and q2 are the amounts of charge, r is the distance between the charges, and k is Coulomb's constant (approximately 9.00 x 10^9 N*(m²/C²)).
Giving the values, we have, 1000 N = 9.00 x 10^9 N*(m²/C²)*((2 x 10^-5 C) * (5 x 10^-6 C))/r².
Solving for r (the distance between the charges) in this equation, we first divide both sides of the equation by the values on the right, excluding r, which gives us: r² = ((2 x 10^-5 C) * (5 x 10^-6 C) * 9.00 x 10^9 N*(m²/C²))/1000N.
Calculating the values in this equation and then taking the square root of the result gives r = 0.134 m or 13.4 cm which is the distance between the two charges.
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Answers
The barge will sink until the sum of the forces on it equals zero.
The two forces are the weight of the barge (with sand) and the buoyancy force, the force exerted by the liquid (fresh water) on the barge.
Then, weight of the barge with sand = m*g = 600 kg * g
Buoyancy force = density of the fluid * Volume of displaced fulid * g
Then, m*g = density of the fulid * Volume of displaced fluid * g
m*g = df * Vf * g
m = df*Vf => Vf = m/df = 600 kg / 1 000 kg/m^3 = 0.6 m^3
The volume of the displaced fluid equals the volume of the portion of the barge sinked, wich is the area of the rectangular base times the depth to which it sinked>
7m*2m*H = 0.6 m^3 => H = 0.6 m^3 /[14 m^2] = 0.043 m = 4.3 cm
Answer: 4.3 cm