What is the equation of a parabola with vertex (0,0) and focus (0,4)?Draw its graph on the grid

Answers

Answer 1
Answer: focus of a parabola: 4p(y-k)=(x-h)^2 where vertex (h,k) p is the distance from vertex to focus
4*4(y-0)=(x-0)^2 \n 16y=x^2 \n y= (1)/(16)x^2

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How would i do number 37?

i will give a thanks if you reply with an answer! :)

Answers

what i would do if i were u i would line up the numbers up on thi line from y axis to x axis put the numbers negative and positive and u plot the numbers then u will get ur answer

hope it helped by explaining : )

Identify a3 of this sequence: 0.25, 0.5, 0.75, 1, 1.25, 1.5, … a3 =

Answers

this sequence can be generated with this function, n being the nth member of the sequence:
f(n) = 0.25(n)

Answer:

0.75

Step-by-step explanation:

i just took the test :)

How do you solve 7 1/5-6 2/5

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7 + 1 2/6 2/5 hope this kinda helps :3

Can someone pleeeeeasssse help with 3x-2/x^2-2x-3 divided by 1/x-3

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If im correct your final answer should be 2x-3/(x+1)(x-3). #TeamAlvaxic

Dilate the figure with the origin as the center of dilation.

(x,y) → (0.5x, 0.5y)​

Answers

Answer:

  see attached

Step-by-step explanation:

The dilation factor of 1/2 moves each point to half its previous distance from the origin.

The multiplication property of equality could be used to solve which of the following equations?(x + 2)(x - 3) = 0
m + 7 = -12
b ÷ (-2) = 18
-3 + y = 7

Answers


b ÷ (-2) = 18
hope it helps

well
first one doesn't need that property
2nd one needs subtraction property of equality
third one can use it
fourth one needs addition property of equality


3rd one is answer
b/-2=18 is answer